Answer:
Small flags = 108
large flags= 47
Step-by-step explanation:
Step one:
given
let the number of small lag be x
and big flags be y
so
3.5x+6.5y= 683.5----------1
x+y=155------------------------2
Step two:
from eqn 2 x= 155-y
put x= 155-y in eqn 1
3.5(155-y)+6.5y= 683.5
542.5-3.5y+6.5y=683.5
collect like terms
3y=141
divide by 3
y= 141/3
y=47
Step three:
put y= 47 in eqn 2
x+47=155
x= 155-47
x=108
Answer:
C) the triangles are congruent
Step-by-step explanation:
Because you are 12 you put down
12
x can be anything so if you write
12x
You can later substitute it for 3. 12(3)
Your uncle is 2 years more
12x+2 is your equation
or
12(3) + 2
(a) 404 subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence.
(b) When the confidence level decreases to 95%, the number of subjects decreases from 404 to 234.
<u>Explanation:</u>
Given:
σ = 15.6
Let the number of subjects be n
(a)
When the confidence level is 99%, then z = 2.576
E = 2
We know:
![n = [\frac{z X s}{E}]^2](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7Bz%20X%20s%7D%7BE%7D%5D%5E2)
On substituting the value, we get:
![n = [\frac{2.576 X 15.6}{2} ]^2\\\\n = 403.7](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B2.576%20X%2015.6%7D%7B2%7D%20%5D%5E2%5C%5C%5C%5Cn%20%3D%20403.7)
Thus, 404 subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence.
(b)
When the confidence level is 95%, then z = 1.96
E = 2
We know:
![n = [\frac{z X s}{E}]^2](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7Bz%20X%20s%7D%7BE%7D%5D%5E2)
On substituting the value, we get:
![n = [\frac{1.96 X 15.6}{2} ]^2\\\\n = 233.7](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B1.96%20X%2015.6%7D%7B2%7D%20%5D%5E2%5C%5C%5C%5Cn%20%3D%20233.7)
n = 234
Thus, when the confidence level decreases to 95%, the number of subjects decreases from 404 to 234.
Factors of 42 are...
1, 2, 3, 6, 7, 14, 21, and 42.
1 x 42 = 42
2 x 21 = 42
3 x 14 = 42
6 x 7 = 42
Don't know how you want your table.
I'm sure you can do it yourself.