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3 years ago

H o w d o t h i s p l e a s e h a l p m e h

Mathematics

2 answers:

xenn [34]3 years ago

4 0

How do you find the area of a parallelogram?
Area=base * height
S0, you multiple 10in by 6in to get 60 inches squared. Hope this helped!

zysi [14]3 years ago

3 0

Area = base * height = 10 * 6 = 60 in^2 Answer

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zhenek [66]

Answer:

its 15 to the square root of 2

Step-by-step explanation:

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3 years ago

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Which expression are equivalent to -3-(7.5+4)

Hunter-Best [27]

-14.5

Basically, -(7.5+4) is -11.5 and then combine -3 with -11.5 which yields -14.5

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3 years ago

one eighth of the brass instruments are tubas. if there are 240 instruments in the band, how many are tubas?

Andrej [43]

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3 years ago

Find the value of x<br><br> 3/4 x-4=8

Vesna [10]

Answer: x = 16

Step-by-step explanation:

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3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

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3 years ago