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3 years ago

If ray JG is an angle bisector of ∠FJH, find m∠FJH.

Mathematics

1 answer:

miss Akunina [59]3 years ago

3 0

Answer:

m∠FJH=60°

Step-by-step explanation:

The complete question is

JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°

What is FJH

we know that

m∠FJH=m∠FJG+m∠GJH -----> equation A

If ray JG is an angle bisector of ∠FJH

then

m∠FJG=m∠GJH -----> equation B

substitute the given values in equation B and solve for x

(2x + 4)°=(3x -9)°

3x-2x=4+9

x=13

Find the measure of angle FJH

m∠FJH=(2x + 4)°+(3x -9)°

substitute the value of x

m∠FJH=(2(13) + 4)°+(3(13) -9)°

m∠FJH=(30)°+(30)°

m∠FJH=60°

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Asked on December 20, 2019 by

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A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

h=32×22×14 cm

×(28)

×h=9856 cm

22×784

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4 0

3 years ago

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An investment website can tell what devices are used to access their site. The site managers wonder whether they should enhance

lbvjy [14]

Answer: a) Unimodal and symmetric

b) 0.26

c) 0.038

Step-by-step explanation:

Given: Sample size of investors (n)= 131

True proportion of smartphone users(p) =26%

a) Since sampling distribution for the sample proportion is approximately normal when n is larger.

Normal distribution is Unimodal and symmetric.

So correct option : Unimodal and symmetric

b) mean of this sampling distribution = p = 0.26

c) standard deviation of the samplingdistribution = $\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26\times (1-0.26)}{131}}=\sqrt{0.00146870229008}$

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3 years ago

The world population is estimated to be 7.8 billion in 2020, and growing at an instantaneous rate of 1.05%. (a) Estimate the pop

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Answer:

Population in 2100 is 17.99 billion.

Step-by-step explanation:

The population of the world in 2020 = 7.8 billion.

The growth rate = 1.05%

Now find the population after 2100. Use the below formula to find the population.

Population in 2100 = Population of 2020 (1 + growth rate)^n

Population in 2100 = 7.8 (1 + 0.0105)^80

Population in 2100 = 17.99 billions.

Now, find the growth rate in 2100.

dN/dt = [r N (K – N) ] / K

r = Malthusian parameter

K = carrying capacity.

Now divide both sides by K, now x = N/K then do the differential equation.

dx/dt = r x ( 1- x)

Now integrate, x(t) = 1/ [ 1 + (1/x – 1) c^-rt

From the first equation = dN/dt = (13 – 7.8) / 80 = (r × 7.8×(13 – 7.8) / 12

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3 years ago

Please help asap! 40 pts

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y+12-12=12-22
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