Answer:
m∠FJH=60°
Step-by-step explanation:
The complete question is
JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°
What is FJH
we know that
m∠FJH=m∠FJG+m∠GJH -----> equation A
If ray JG is an angle bisector of ∠FJH
then
m∠FJG=m∠GJH -----> equation B
substitute the given values in equation B and solve for x
(2x + 4)°=(3x -9)°
3x-2x=4+9
x=13
Find the measure of angle FJH
m∠FJH=(2x + 4)°+(3x -9)°
substitute the value of x
m∠FJH=(2(13) + 4)°+(3(13) -9)°
m∠FJH=(30)°+(30)°
m∠FJH=60°
