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3 years ago

In the graph, what are the x and y coordinates of the center?

Mathematics

2 answers:

Vlad [161]3 years ago

7 0

Answer:

I'd go with a solid (-1,2)

Step-by-step explanation:

Look at the center?

babunello [35]3 years ago

3 0

Answer:

-1, 2

Step-by-step explanation:

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What is the midpoint between points (1, 4) and (9, 16)?

Ostrovityanka [42]

To find the midpoint you find the average x and the average y values. The average of 1 and 9 is 5, and the average of 4 and 16 is 10. The midpoint would be (5,10).

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3 years ago

3) -x + 15 = x + 6 - 5

Vikentia [17]

Answer: 17

but before you put that was the '3' included?

Step-by-step explanation:

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3 years ago

If P is the circumcenter △ A B C, and AD =3x - 11, DB =5x - 29, PC =18, find DP.

Basile [38]

Answer:

15.6

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Give a third degree polynomial that has zeros of 13, 5i, and −5i, and has a value of −680 when x=3. Write the polynomial in stan

Vikki [24]

Answer:

$\dfrac{17x^3-221x^2+425x-5525}{9}\\$

Step-by-step explanation:

hello

we need to find something like, a being real

$a(x-13)(x-5i)(x+5i)$

with a so that

$a(3-13)(3-5i)(3+5i)=-680\\\\a(-10)(3^2-(5i)^2)= -10(9+25)a=-360a=-680\\ a = \dfrac{680}{360}=\dfrac{17*40}{9*40}=\dfrac{17}{9}$

so the third degree polynomial that we are looking for is

$\dfrac{17}{9}(x-13)(x-5i)(x+5i)\\=\dfrac{17}{9}(x-13)(x^2+25)\\\\=\dfrac{17}{9}(x^3+25x-13x^2-13*25)\\\\\\=\dfrac{17}{9}(x^3-13x^2+25x-325)\\\\\\\\=\dfrac{17}{9}x^3-\dfrac{17*13}{9}x^2+\dfrac{17*25}{9}x-\dfrac{17*325}{9}\\=\dfrac{17}{9}x^3-\dfrac{221}{9}x^2+\dfrac{425}{9}x-\dfrac{5525}{9}\\$

hope this helps

3 0

4 years ago

5 Simplify (12)(129). Write your answer using an exponent.<br> Explain how you found your answer.

katrin2010 [14]

Answer:

Your answer would 1,548. You would multiply the two numbers, as numbers in parentheses immediately next to each with no symbol of mathematics between them means multiplication, you would just multiply them. Hope this helps!

7 0

3 years ago