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Serhud [2]
3 years ago
5

Does anyone know how to solve this ratio?

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

The answer to this question is 11:3

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Please help!    Which equations are equivalent to the given equation? 3x = -12
uysha [10]
The answer is the 3x divided by 3 = -12 divided by 3
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3 years ago
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Please please need help with this one having a hard time with it.
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Ummmmmm where’s the pic?
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The GRE is an entrance exam that many students are required to take in order to apply to graduate school. In 2014, the combined
zlopas [31]

The probability that a randomly selected score is greater than 334 will be 0.02275.

<h3>What is a normal distribution?</h3>

The Gaussian Distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The GRE is an entrance exam that many students are required to take in order to apply to graduate school. In 2014, the combined scores for the Verbal and Quantitative sections were approximately normally distributed with a mean of 310 and a standard deviation of 12.

Then the probability that a randomly selected score is greater than 334 will be

The z-score is given as

z = (x - μ)/σ

z = (334 - 310)/12

z = 24/12

z = 2

Then the probability will be

P(x > 334) = P(z > 2)

P(x > 334) = 1 - P(x<334)

P(x > 334) = 1 - 0.97725

P(x > 334) = 0.02275

More about the normal distribution link is given below.

brainly.com/question/12421652

#SPJ1

6 0
2 years ago
Fill in the missing number.3 meters=______cm
Brut [27]

Answer:

300

Step-by-step explanation:

there are 100 cm in a meter (I believe)

8 0
3 years ago
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What is the following sum?<br> 5(3squareroot x) +9 (3squareroot x)
Volgvan

\sf{14(\sqrt[3]{x}) }

Step-by-step explanation:

5(\sqrt[3]{x})+9(\sqrt[3]{x})\\\\(5+9)(\sqrt[3]{x})\\\\14(\sqrt[3]{x})

7 0
3 years ago
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