What is the sum of 1/10 of 7?

Plz Work out -1x(6x-8)=

Andrew [12]

-1x(6x - 8)

= -x(6x - 8)

= -x(6x) - x(-8)

= -6x^2 + 8x

4 0

3 years ago

Help please will give brainliest PLEASE<br><br><br>I accidentally chose that

kherson [118]

Answer:

I think its the third one but i might be wrong

Step-by-step explanation:

5 0

3 years ago

Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.

eimsori [14]

Answer:

(a) $5^{8}$

(b) 3

(c) 27

(d) $\dfrac{1}{6}$

Step-by-step explanation:

We need simplify the given expressions.

(a)

Consider the given expression is

$(5^4)(25^2)$

$(5^4)((5^2)^2)$

Using the properties of exponents we get

$(5^4)(5^4)$ $[\because (a^m)^n=a^{mn}]$

$5^{4+4}$ $[\because a^ma^n=a^{m+n}]$

$5^{8}$

(b)

Consider the given expression is

$(9^{\frac{1}{3}})(3^{\frac{1}{3}})$

$((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})$

Using the properties of exponents we get

$(3^{\frac{2}{3}})(3^{\frac{1}{3}})$ $[\because (a^m)^n=a^{mn}]$

$3^{\frac{2}{3}+\frac{1}{3}}$ $[\because a^ma^n=a^{m+n}]$

$3^{1}$

$3$

(c)

Consider the given expression is

$(\dfrac{1}{3})^{-3}$

Using the properties of exponents we get

$(\dfrac{3}{1})^{3}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$3^{3}$

$27$

(d)

Consider the given expression is

$(6^4)(6^{-5})$

Using the properties of exponents we get

$6^{4+(-5)}$ $[\because a^ma^n=a^{m+n}]$

$6^{-1}$

$\dfrac{1}{6^{1}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{1}{6}$

6 0

3 years ago

Jocelyn invested $390 in account paying an interest rate of 2.7% compounded daily. Assuming no deposits or withdrawals are made,

Bond [772]

Answer:

Someone ples answer this

Step-by-step explanation:

It’s so hard

8 0

3 years ago

Find the upper 20%of the weight?

meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is $X = 0.84\sigma + \mu$ , in which $\sigma$ is the standard deviation of all weights and $\mu$ is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

$Z = \frac{X - \mu}{\sigma}$

$0.84 = \frac{X - \mu}{\sigma}$

$X = 0.84\sigma + \mu$

The upper 20% of the weighs are weights of at least X, which is $X = 0.84\sigma + \mu$ , in which $\sigma$ is the standard deviation of all weights and $\mu$ is the mean.

6 0

3 years ago