When the center of Earth is 3.8 × 105 kilometers from the center of the moon, the force of gravity between Earth and the moon is
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Answer:
Step-by-step explanation:
Hello!
The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.
Sample 1: Advanced tennis players
X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.
n₁= 6
X[bar]₁= 40.29 N
S₁= 11.29
Sample 2: Intermediate players
X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.
n₂= 8
X[bar]₂= 21.40
S₂= 8.30
Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.
If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:
H₀: μ₁ ≤ μ₂
H₁: μ₁ > μ₂
α: 0.05
Using the p-value approach, the decision rule is
If p-value ≤ α, reject the null hypothesis
If p-value > α, do not reject the null hypothesis
The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.
This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.
I hope this helps!
Step-by-step explanation:
Take the first derivative
Set the derivative equal to 0.
or
For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function
So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function
So the local min occurs at -2, at x=1