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hodyreva [135]
3 years ago
7

I need help please because it’s like 11pm at night and I am so tired and I have to wake up at 5am tomorrow so can someone please

help me so I can go to sleep PLEASE i will give you a thanks and 8 points just PLEASE HELP ME

Mathematics
1 answer:
V125BC [204]3 years ago
4 0

Answer:

She is not correct.

Step-by-step explanation:

If she originally purchases the teas for $100 and then she marks the price up 20%, the retail price would then be 100 + 0.20(100) = 100 + 20 = 120. The sales price would then be 120 - 0.2(120) = 120 - 24 = 96. This is less than the purchase price, so she is losing money, rather than gaining.

I hope this helps. If you download an app called Slader, it has the same math book you are using with the answers.

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Answer:

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Exact Form:

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Decimal Form:

0.01506591…

Step-by-step explanation:

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8. For many computer tablets, the owner can set a 4-digit pass code to lock the device.
Anton [14]

Answer:

a. There 5040 different pass codes if the digits cannot be repeated

b. The probability that the pass code is 1234 is ≈ 0.0002

c.  The probability that two people both have a pass code of 1234 is 4×10^{-8}

Step-by-step explanation:

a. How many different 4-digit pass codes are possible if the digits cannot be repeated?

There are

  • 10 possibilities for the first digit
  • 9 possibilities for the second digit
  • 8 possibilities for the third digit
  • 7 possibilities for the fourth digit

Thus there are  10×9×8×7=5040 different pass codes

b. If the digits of a pass code are chosen at random and without replacement from the digits, what is the probability that the pass code is 1234

The probability that the first digit is 1 is \frac{1}{10}

The probability that the second digit is 2 is \frac{1}{9}

The probability that the second digit is 3 is \frac{1}{8}

The probability that the fourth digit is 4 is \frac{1}{7}

Thus  the probability that the pass code is 1234 is \frac{1}{10} * \frac{1}{9} *\frac{1}{8} *\frac{1}{7} =\frac{1}{5040} ≈ 0.0002

c. The probability that two people, who both chose a pass code by selecting digits at random and without replacement, both have a pass code of 1234?

The probability that the pass code of the one person is 1234 is 0.0002

The probability that the pass code of the other person is 1234 is 0.0002

Thus, the probability that two people have both pass code of 1234 is

0.0002×0.0002 = 4×10^{-8}

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4 years ago
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