In a triangle, the midline joining the midpoints of two sides is parallel to the third side and half as long
2(5x+2) = 3x + 32
10x + 4 = 3x + 32
10x - 3x = 32 - 4
7x = 28
x = 28/7
x = 4
The length of the midsegment = 5x+2 = 5·4 + 2 = 22
Direct computation:
Parameterize the top part of the circle
by

with
, and the line segment by

with
. Then



Using the fundamental theorem of calculus:
The integral can be written as

If there happens to be a scalar function
such that
, then
is conservative and the integral is path-independent, so we only need to worry about the value of
at the path's endpoints.
This requires


So we have

which means
is indeed conservative. By the fundamental theorem, we have

Answer:
In Δ CFD , CD is the LONGEST side.
Step-by-step explanation:
Here, the given Δ CSD is a RIGHT ANGLED TRIANGLE.
Now, as we know in a right triangle, HYPOTENUSE IS THE LONGEST SIDE.
So, in Δ CSD SD is the longest side as SD = Hypotenuse.
Now, an altitude CF is drawn to hypotenuse SD.
⇒ CF ⊥ SD
⇒ Δ CFD is a RIGHT ANGLED TRIANGLE with ∠ F = 90°
and CD as a hypotenuse.
⇒ In Δ CFD , CD is the LONGEST side.
Hence, CD is the longest side in the given triangle CFD.
Step-by-step explanation:
Option D is the correct answer because we will cross multiply
4/6 = 9/x
4x = 54
X = 27/2