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3 years ago

Is y=2x+5 a example of a proportional realationship

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

7 0

No it's as n example of a equality

mixer [17]3 years ago

4 0

No it is not a proportional relationship. If you remember y=mx+b, and your equation is y=2x+5. If the equation has a "b", in this case your B is 5, it is non-proportional.

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What is the surface area of 2cm, 5cm, and 2cm

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3 years ago

Statements that are true for a cylinder with radius r and height h.

vampirchik [111]

Answer:

Only the second and third statements are correct:

Doubling r quadruples the volume.

Doubling h doubles the volume.

Step-by-step explanation:

The volume of a cylinder is given by:

$\displaystyle V=\pi r^2h$

We can go through each statement and examine its validity.

Statement 1)

If the radius is doubled, our new radius is now 2r. Hence, our volume is:

$\displaystyle V=\pi (2r)^2h=4\pi r^2h$

So, compared to the old volume, the new volume is quadrupled the original volume.

Statement 1 is not correct.

Statement 2)

Using the previous reasonsing, Statement 2 is correct.

Statement 3)

If the height is doubled, our new height is now 2h. Hence, our volume is:

$V=\pi r^2(2h)=2\pi r^2h$

So, compared to the old volume, the new volume has been doubled.

Statement 3 is correct.

Statement 4)

Statement 4 is not correct using the previous reasonsing.

Statement 5)

Doubling the radius results in 2r and doubling the height results in 2h. Hence, the new volume is:

$V=\pi (2r)^2(2h)=\pi (4r^2)(2h)=8\pi r^2h$

So, compared to the old volume, the new volume is increased by eight-fold.

Statement 5 is not correct.

7 0

3 years ago

What is the length of BD?

I am Lyosha [343]

Answer:

$10\sqrt{3}$

Step-by-step explanation:

Trigonometric Ratios

This problem will be solved by the use of a trigonometric ratio called sine because it relates the opposite side of a given angle with the hypotenuse of the triangle.

Selecting the angle of 60° in triangle ABD:

Sine Ratio

$\displaystyle \sin 60^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}$