A card is drawn at random from a deck. what is the probability that it is an ace or a king?

1 answer:

hjlf3 years ago

6 0

There are 52 cards. Of this, there are 4 aces (one of each of the four suits) and 4 kings. There are 4+4 = 8 cards that are either an ace or a king (but not both). Note that the events "drawing an ace" and "drawing a king" are mutually exclusive. Being mutually exclusive means its impossible to have both events occur simultaneously for any single card.

So there are 8 cards we want (ace or king) out of 52 total

Dividing the two values, and reducing fully, gives:
8/52 = (4*2)/(4*13) = 2/13

The final answer as a fraction is 2/13

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Please help with the problem

worty [1.4K]

Answer:

95%

Step-by-step explanation:

0.6 of 40 is 24, she bought 24 green balloons.

24 × 1.5 = 36, she bought 36 yellow balloons.

So we have

40 red

24 green

36 yellow

Then from the rest of the information, 2 red, 2 green, and 1 yellow balloon all popped.

We now have

38 red

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35 yellow

for a total of:

95 balloons out of 100 original balloons, 95%

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2 years ago

What is f(-2) for f(x) = x^2+3x=5

leva [86]

f(x) = x^2+3x+5

f(-2) = (-2)^2 +3(-2)+5

f(-2) = 4-6+5

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3 years ago

Read 2 more answers

What is the interquartile range of the data set?

anastassius [24]

The interquartile range of the data set will be 30.

Explanation

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, 30, 40, 40, 48, 50, 55, 60, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30

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3 years ago

Find the other endpoint (E2) given the midpoint (2,2) and endpoint 1 (-3,-2)

Amiraneli [1.4K]

Answer:

( $-\frac{1}{2}$ ,0)