Answer:
Step-by-step explanation:
b) 1- scale factor from the first map to the second map:
= 1.33
2- landmark on the first map is a triangle with side lengths of 3 mm, 4 mm, and 5 mm.
Side lengths of the landmark on the second map
Divide the length by scale factor:
side lengths of 3 mm:
= 2.25 mm
side lengths of 4 mm:
= 3.007 mm
side lengths of 5 mm:
= 3.75 mm
Answer:
(minus 6) (7) 19_38_2773_9938_377449
Answer:
34%
Step-by-step explanation:
because 1/4 is 25%
Answer:
$4.48
Step-by-step explanation:
It takes $1.12 to feed one kid, to find the cost of all four kids we multiply 1.12 by 4
1.12*4 = $4.48
Answer:
D) 239
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.99}{2} = 0.005](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.99%7D%7B2%7D%20%3D%200.005)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 2.575](https://tex.z-dn.net/?f=z%20%3D%202.575)
Now, find the margin of error M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
Required sample size:
Is n
n is found when ![M = 6](https://tex.z-dn.net/?f=M%20%3D%206)
We have that ![\sigma = 36](https://tex.z-dn.net/?f=%5Csigma%20%3D%2036)
So
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![6 = 2.575*\frac{36}{\sqrt{n}}](https://tex.z-dn.net/?f=6%20%3D%202.575%2A%5Cfrac%7B36%7D%7B%5Csqrt%7Bn%7D%7D)
![6\sqrt{n} = 36*2.575](https://tex.z-dn.net/?f=6%5Csqrt%7Bn%7D%20%3D%2036%2A2.575)
Simplifying by 6
![\sqrt{n} = 6*2.575](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%206%2A2.575)
![(\sqrt{n})^{2} = (6*2.575)^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%286%2A2.575%29%5E%7B2%7D)
![n = 238.7](https://tex.z-dn.net/?f=n%20%3D%20238.7)
We round up, and the answer is 239.