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3 years ago

Which expression is equivalent to 6^2\cdot4^36

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

is 5

Step-by-step explanation:i did the test and i remember that question

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Find m∠DFC. A. 23 B. 167 C. 46 D. 69

pochemuha

Answer:

A.23

maaf kalosalah !(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!

8 0

3 years ago

Find the distance between the points: (–6, 7) and (–1, –5). In your final answer, include the formula and calculations that you

expeople1 [14]

Answer: The distance between the points (-6,7) and (-1,-5) is 13 units.

Solution:

P1=(-6,7)=(x1,y1)→x1=-6, y1=7

P2=(-1,-5)=(x2,y2)→x2=-1,y2=-5

Distance between points P1 and P2: d=?

d=sqrt [ (x2-x1)^2 + (y2-y1)^2 ]

Replacing the knwon values:

d=sqrt [ (-1-(-6))^2 + (-5-7)^2 ]

d=sqrt [ (-1+6)^2 + (-12)^2 ]

d=sqrt [ (5)^2 + 144 ]

d=sqrt [ 25 + 144 ]

d=sqrt [ 169 ]

d=13

4 0

3 years ago

Read 2 more answers

jimmy is building a frame for his square garden he doesnt want the garden to be any bigger than 100ft squared what is the bigges

S_A_V [24]

100 divided by 4 so 25 feet on each side

8 0

4 years ago

Marcel made an error when he used the distributive property to solve the problem shown. Which sentence describes the error? In S

nordsb [41]

The picture with the complete question is attached below :

Answer:

In Step 2, 90 should be multiplied by the quantity 10 – 12, not by 10

Step-by-step explanation:

90 * x - 90 * 12 = 90(x - 12)

From the question, x = 10

Hence,

90(10 - 12)

(90* 10) - (90 * 12) - - - > correct evaluation

900 - 1080

= - 180

Hence, both values in the bracket, that is 10 and - 12 should be multiplied by 90. Not just 10 alone.

3 0

3 years ago

Find at least three different sequences beginning with the terms 3, 5, 7 whose terms are generated by a simple for- mula or rule

pychu [463]

1. Perhaps the simplest rule is one that makes this the start of an arithmetic sequence:

$a_{n+1}=a_{n}+2$

Then the sequence will continue ...

... 3, 5, 7, 9, 11, 13, 15, ...

2. We can multiply the two terms by some values, add the results, then add some constant. There are an infinite number of ways to choose such values. Here's one set of numbers that give the third term from the first two:

$a_{n+2}=4a_n-a_{n+1}$

Then the sequence will continue ...

... 3, 5, 7, 13, 15, 37, 23, ...

3. We can multiply adjacent values and add a constant.

$a_{n+2}=a_{n+1}\cdot a_n-8$

Then the sequence will continue ...

... 3, 5, 7, 28, 188, 5256, 988120, ...

5 0

3 years ago