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lukranit [14]
2 years ago
11

A recent survey by the American Cancer Society shows that the probability that someone is a smoker is P(S) = 0.19. It has also d

etermined that the probability that someone has lung cancer, given that he or she is a smoker, is P(LC|S) = 0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S ∩ LC)?
0.03
0.83
0.35
0.02
Mathematics
1 answer:
Rom4ik [11]2 years ago
8 0
P(LC / S) = P(S intersect LC) / P(S)
P(S intersect LC) = P(S)*P(LC / S) = 0.19 * 0.158 = 0.03
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Evaluate 3xy with an exponent of 2 y, if x=2 and y=5
Bogdan [553]

Answer:

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Step-by-step explanation:

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Putting the values of x and y in the expression

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=3(2)(25)-5

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What is the quotation of -3/8 and -1/3
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Step-by-step explanation:

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1 year ago
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The slope of a line is undefined, and the x-intercept is -7. what is the equation of the line?​
Andreyy89

The equation of line with undefined slope and x - intercept -7 is x = -7

<em><u>Solution:</u></em>

Given that the slope of line is undefined and the x intercept is -7

To find: Equation of line

If a line has undefined slope, then it is a vertical line

A vertical line has undefined slope because all points on the line have the same x-coordinate

<em><u>The equation of a vertical line always takes the form:</u></em>

x = b

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7 0
3 years ago
Find the distance between the lines<br> Y=3x+10<br> Y=3x-20<br> AND <br> Y=3/2x+3/2<br> Y=3/2x-5
rosijanka [135]
At first we need to know how to find the distance between two parallel lines
The parallel lines which have the same slope 
If we have two parallel lines ⇒ y₁ = mx + c₁   and    y₂ = mx + c₂
So, the distance between y₁ and y₂ = d = \frac{|c_{1} - c_{2}|}{\sqrt{1 + m^{2}}}
========================================================

Part (1):
=======

<span>The distance between the lines
</span>
<span> Y₁ = 3x + 10    and       Y₂ = 3x - 20</span>
∴ m = 3  , c₁ = 10  and  c₂ = -20
∴ d = \frac{| 10 - (-20)|}{\sqrt{1 + 3^{2}}}= \framebox{9.5}

========================================================

Part (2):
=======

<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span>    and       Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5  , c₁ = 3/2 = 1.5   and  c₂ = -5
∴ d = \frac{| 1.5- (-5)|}{\sqrt{1 + 1.5^{2}}}= \framebox{3.6}

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Plz, answer the question in the photo.
Mamont248 [21]

Answer:

2/5

Step-by-step explanation:

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