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lukranit [14]
3 years ago
11

A recent survey by the American Cancer Society shows that the probability that someone is a smoker is P(S) = 0.19. It has also d

etermined that the probability that someone has lung cancer, given that he or she is a smoker, is P(LC|S) = 0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S ∩ LC)?
0.03
0.83
0.35
0.02
Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0
P(LC / S) = P(S intersect LC) / P(S)
P(S intersect LC) = P(S)*P(LC / S) = 0.19 * 0.158 = 0.03
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If the answer is above 1/2 inch round it to 1 inch, if it is below 1/2 inch round it to 0, or the nearest  number below it....hope it helps

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Answer:

16 1/3 lbs

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We can write a ratio to solve

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3 years ago
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Answer:

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3 years ago
A manager recorded how many hours each of 11 cashiers worked in a week. Which interval contains the median number of hours worke
Lana71 [14]

Answer:

Step-by-step explanation:

Hello!

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To identify the median you have to calculate it's position:

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The fifth interval corresponds to 40 - 50 worked hours and only one worker recorded these working hours.

The first five workers were recorded in the first two intervals and the sixth worker was recorded in the fourth interval. So the interval that contains the median number of hours worked is "30 - 40 hours"

I hope this helps!

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3 years ago
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