You are competing in a race. The table shows the times from last year's race you want your time to be last year's median time wi
th an absolute
deviation of at most 5 minutes. Complete the inequality to represent the time in minutes) you hope to achieve
deviation of at most 5 minutes. Complete the inequality to represent the time in minutes) you hope to achieve
1 answer:
Answer:
Step-by-step explanation:
Let's arrange the numbers from least to greatest:
20, 25, 27, 28, 31, 32, 32, 38, 40, 40, 42, 48
The median is the "middle" number when arranged from least to greatest.
There are 12 numbers, so the middle number would be "average" of 6th and 7th terms.
6th term = 32
7th term = 32
Average = (32+32)/2 = 32
Hence, median = 32
Absolute deviation of 5 minutes means 5 minutes less or greater than the median, 32.
So, 32 - 5 = 27 & 32 + 5 = 37
Hence
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The correct answer is A.
You have direct variation if x and y are modeled by the equation
In this case, m is the constant of proportionality. So, if the constant has to be 2, the equation becomes
A side note: Actually, option C has a constant of proportionality of two as well, except the roles of x and y are interchanged. I chose option A because usually you want the y = mx form, but the names of the variables are obviously meaningless.