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3 years ago

(9^3)^2 Hurrrrryyyyyyyyyyyyyy

Mathematics

1 answer:

uranmaximum [27]3 years ago

3 0

Answer: 531441

Step-by-step explanation:

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Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% chance that the land has oil.

Anna [14]

In this case you the probabilities can be multiplied similarly to if you flipped a coin twice. .45 * .80 = .36

5 0

3 years ago

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Divide round your answer to the nearest hundredth 5608.67÷7

Likurg_2 [28]

Answer:

5608.67 ÷ 7 = 801.24

4 0

3 years ago

add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s

Molodets [167]

<h2>Perfect Squares</h2>

Perfect square formula/rules:

$a^2+2ab+b^2=(a+b)^2$
$a^2-2ab+b^2=(a-b)^2$

Trinomials are often organized like $ax^2+bx+c$ .

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

Perfect square trinomial: $ax^2+bx+(\dfrac{b}{2})^2$
or $ax^2-bx+(\dfrac{b}{2})^2$

<h2>Solving the Question</h2>

We're given:

$c^2-4c$

In a trinomial, we're given the $ax^2$ and $bx$ values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

4 ÷ 2 = 2
2² = 4

Therefore, the term that we can add is + 4.

$c^2-4c+4$

To write this as the square of a bracketed expression, we can follow the rule $a^2-2ab+b^2=(a-b)^2$ :

$(c-2)^2$

<h2>Answer</h2>

$c^2-4c+4$

$(c-2)^2$

4 0

1 year ago

B>13/9 interval notation

BartSMP [9]

Interval Notation of b > 13/9 is [13/9, infinity)

3 0

2 years ago

Find the surface area plz

vladimir1956 [14]

Hi again! ;)

If we want to find the surface area of a cube, we need to find the area of one surface first, and then multiply that by 9, since there are 9 sides/surfaces on a cube.

Since each side of a square is the same, we first find the area of one surface:

9 × 9 = 81

Then, to find the surface area, we multiply 81 by 6:

81 × 6 = 486

The surface area is
$486 \: {in}^{2}$

7 0

2 years ago