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Sunny_sXe [5.5K]
3 years ago
6

PLEASE HELP!! WILL GIVE BRAINLIEST!!!

Mathematics
2 answers:
valina [46]3 years ago
8 0

Answer:

the answer is the fourth option or D

Step-by-step explanation:

Murrr4er [49]3 years ago
7 0

Answer:

option D

Step-by-step explanation:

Jerry solved this equation: 

3(x-\frac{1}{4})=\frac{13}{6}

In the first step , she multiplied 3 inside the parenthesis

1. 3x-\frac{3}{4}=\frac{13}{6}

In step 2, 3/4 is added on both sides

2. 3x-\frac{3}{4}+\frac{3}{4}=\frac{13}{6}+\frac{3}{4}

In step 3, we take LCD 12

3. 3x=\frac{26}{12}+\frac{9}{12}

In step 4, add the fractions

4. 3x=\frac{35}{12}

Here, 3 or 3/1 are same.

\frac{3}{1}x=\frac{35}{12}

In step 5, to remove 3/1 we multiply both sides by 1/3.

Instead of multiplying 1/3 , Jerry made an error by multiplying 3/1

\frac{1}{3} \cdot \frac{3}{1}x=\frac{1}{3} \cdot \frac{35}{12}

x=\frac{35}{36}

In step 5, he should have multiplied both sides by 1/3

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Find the equation of the line
Elis [28]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 6x - 2 ← is in slope- intercept form

with slope m = 6

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{6}, thus

y = - \frac{1}{6} x + c ← is the partial equation

To find c substitute (6, - 2 ) into the partial equation

- 2 = - 1 + c ⇒ c = - 2 + 1 = - 1

y = - \frac{1}{6} x - 1 ← equation of line

6 0
3 years ago
Can you answer this one
qaws [65]

Answer:

P'(-6,-4)

Step-by-step explanation:

By translating the point under the translation, to put it into a simpler form, it says to move the point 4 units to the left and 6 units down. Using this, the point will move to P'(-6,-4)

5 0
3 years ago
Read 2 more answers
Given that f(x) = x^2 – 2x - 63 and g(x) = x + 7, find (f - g)(x)
Juliette [100K]

Answer:

(f - g)(x) = x² - 3x - 70

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 2x - 63

g(x) = x + 7

(f - g)(x) is f(x) - g(x)

<u>Step 2: Find (f - g)(x)</u>

  1. Substitute:                               (f - g)(x) = x² - 2x - 63 - (x + 7)
  2. Distribute -1:                            (f - g)(x) = x² - 2x - 63 - x - 7
  3. Combine like terms (x):          (f - g)(x) = x² - 3x - 63 - 7
  4. Combine like terms (Z):          (f - g)(x) = x² - 3x - 70
3 0
3 years ago
John drives at an average speed of 40 miles per hour for the first 5 hours of the 655 mile trip to buffalo. Charlie then drives
Elodia [21]
65mph

John drove a total of 200 miles (40mph•5)
655-200= 455 miles
Charlie drove this in seven hours, and 455mi/7hours = 65mph
5 0
3 years ago
4x+y=8 and x+3y=8 graphed
IRISSAK [1]
standard \ linear \ equation\ :\\\\y=ax+b\\\\ \begin{cases} 4x+y=8\ \ |\ subtract\ 4x\ to\ both\ sides\\ x+3y=8 \ \ |\ subtract\ x\ to\ both\ sides \end{cases}\\\\\begin{cases} y=-4x+8 \\ 3y=-x+8\ \ | \ divide \ each \ term \ by \ 3 \end{cases}

\begin{cases} y=-4x+8 \\ y=-\frac{1}{3}x+\frac{8}{3} \end{cases}\\\\y=-4x+8\\ To \ find \ the \ x-axis \ intersection \ point, \\set \ y \ equal \ to \ zero \ and \ solve \ for \ x : \\ \\y=0 \ \to 0=-4x+8\\\\4x=8 \ \ | \ divide \ both \ sides\ by\ 4 \\\\x=2\\\\ point : \ \ (2,0)
 
To \ find \ the \ y-axis \ intersection \ point, \\set \ x \ equal \ to \ zero \ and \ solve \ for \ y : \\ \\x=0 \ \to y=-4 \cdot 0+8\\ y=8 \\ point: \ \ (0,8)


y=-\frac{1}{3}x+\frac{8}{3}\\\\ \ the \ x-axis \ intersection \ point \\ \\y=0 \ \to 0=-\frac{1}{3}x+\frac{8}{3}\\ \frac{1}{3}x=\frac{8}{3} \ \ | \ multiply\ both\ sides\ by\ 3 \\\\x=8 \\\\point: \ \ (8,0)

the \ y-axis \ intersection \ point \\ \\x=0 \ \to y=-\frac{1}{3} \cdot 0+\frac{8}{3} \\ y=\frac{8}{3} \\ point : \ \ (0,\frac{8}{3})


Answer :\\\\ \begin{cases} y=-4x+8 \ \ | \ multiply \ each \ term \ by \ (-3) \\ 3y=-x+8 \end{cases}\\\begin{cases} -3y=12x-24 \\ 3y=-x+8 \end{cases}\\+-------\\0=11x-16\\11x=16\ \ | \ divide \ both \ sides\ by\ 11\\x=\frac{16}{11}

y=-4 \cdot \frac{16}{11}+8 \\ y=- \frac{ 64}{11}+\frac{88}{11}\\y= \frac{24}{11}\\\\\begin{cases} x=\frac{16}{11} \\ y=\frac{24}{11} \end{cases}


3 0
3 years ago
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