Answer:
option D
Step-by-step explanation:
Jerry solved this equation:
![3(x-\frac{1}{4})=\frac{13}{6}](https://tex.z-dn.net/?f=3%28x-%5Cfrac%7B1%7D%7B4%7D%29%3D%5Cfrac%7B13%7D%7B6%7D)
In the first step , she multiplied 3 inside the parenthesis
1. ![3x-\frac{3}{4}=\frac{13}{6}](https://tex.z-dn.net/?f=3x-%5Cfrac%7B3%7D%7B4%7D%3D%5Cfrac%7B13%7D%7B6%7D)
In step 2, 3/4 is added on both sides
2. ![3x-\frac{3}{4}+\frac{3}{4}=\frac{13}{6}+\frac{3}{4}](https://tex.z-dn.net/?f=3x-%5Cfrac%7B3%7D%7B4%7D%2B%5Cfrac%7B3%7D%7B4%7D%3D%5Cfrac%7B13%7D%7B6%7D%2B%5Cfrac%7B3%7D%7B4%7D)
In step 3, we take LCD 12
3. ![3x=\frac{26}{12}+\frac{9}{12}](https://tex.z-dn.net/?f=3x%3D%5Cfrac%7B26%7D%7B12%7D%2B%5Cfrac%7B9%7D%7B12%7D)
In step 4, add the fractions
4. ![3x=\frac{35}{12}](https://tex.z-dn.net/?f=3x%3D%5Cfrac%7B35%7D%7B12%7D)
Here, 3 or 3/1 are same.
![\frac{3}{1}x=\frac{35}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B1%7Dx%3D%5Cfrac%7B35%7D%7B12%7D)
In step 5, to remove 3/1 we multiply both sides by 1/3.
Instead of multiplying 1/3 , Jerry made an error by multiplying 3/1
![\frac{1}{3} \cdot \frac{3}{1}x=\frac{1}{3} \cdot \frac{35}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Ccdot%20%5Cfrac%7B3%7D%7B1%7Dx%3D%5Cfrac%7B1%7D%7B3%7D%20%5Ccdot%20%5Cfrac%7B35%7D%7B12%7D)
![x=\frac{35}{36}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B35%7D%7B36%7D)
In step 5, he should have multiplied both sides by 1/3