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aliina [53]
3 years ago
14

Samantha opened a savings account and deposited $8192. The account earns 10% in interest annually. She makes no further deposits

and does not withdraw any money. In t years, she has $25,710 in this account. Write an equation in terms of t that models the situation.
Mathematics
2 answers:
Leokris [45]3 years ago
4 0
The formula for this is A=P(1+r/n)^nt
Where A is the total amount. P is the principal amount. 1 represent 100%. R is the rate. N is the number for annual, quarter, or etc. T is the time given in the question. If you put the numbers that is given in the question and put it in the formula, you will have:
$25,710 = $8192(1 + 0.10/12)^12t
3.14= (1.00833333)^12t
12t= log1.00833333 3.14
t= (log1.00833333 3.14)/12
t is approximately 11.5 yrs
Usimov [2.4K]3 years ago
3 0

Answer: 8192⋅(1.10)t

Step-by-step explanation:

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Step-by-step explanation:

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We must find the value of x, which is the number of gallons used to travel 144 miles.

Cross multiply the ratios.

192 x = 8 × 144

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two Brothers Marvin Lewis each invest $5000 into an account that earns 5% interest neither brothers deposit or withdraw anything
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2 years ago
Find cos(2*ABC) 100POINTS
juin [17]

Answer:

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Step-by-step explanation:

<u>Trigonometric Identities</u>

\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

  • \cos(\angle ABC)=\dfrac{3}{5}
  • \sin(\angle ABC)=\dfrac{4}{5}

Therefore, using the trig identities and ratios:

\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}

7 0
2 years ago
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