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2 years ago

Solve inequality 5x+3>48

Mathematics

2 answers:

7nadin3 [17]2 years ago

7 0

Answer:

x > 9

Step-by-step explanation:

Simply solve for x.

What we have to do is subtract 3 from both sides, then divide by 5 to both sides.

5x > 45

x > 9

x is greater than 9.

#teamtrees #WAP (Water And Plant)

lesya692 [45]2 years ago

4 0

Answer:

x>9

Step-by-step explanation:

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Solve 2(4 x + 3) < 5 x + 21. { x | x < 9} { x | x > -5} { x | x > -9} { x | x < 5}

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Answer:

x <5

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2(4 x + 3) < 5 x + 21

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For what value of x is sq 896z^15/225z^6 = xz^4/15

Ratling [72]

Answer:

Value of x is, 8

Step-by-step explanation:

Given: $\sqrt{\frac{896z^{15}}{225z^6}} =\frac{xz^4}{15} \sqrt{14z}$ ,.....[1]

To find the value of x:

Using exponent rules:

$(a^n)^m = a^{nm}$

$a^n \cdot a^m = a^{n+m}$

Taking square both sides in [1] we have;

$\frac{896z^{15}}{225z^6} = (\frac{xz^4}{15})^2 \cdot (14z)$

Simplify:

$\frac{896z^{15}}{225z^6} =\frac{x^2z^8}{225} \cdot (14z)$

$\frac{896z^{15}}{225z^6} =\frac{14x^2z^9}{225}$

Multiply both sides by $\frac{225}{14z^9}$ we get;

$x^2 = \frac{896 z^{15}}{225z^6} \times \frac{225}{14 z^9} = \frac{896 z^{15}}{14 z^{9+6}}$

Simplify:

$x^2 = \frac{896 z^{15}}{14 z^{15}} = 64$

$x = \sqrt{64}$

Simplify:

x = 8

Therefore, the value of x is, 8

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