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3 years ago

Lucia drew a net for the design of her art project. Which term best describes the three-

Mathematics

1 answer:

meriva3 years ago

8 0

Answer:

Triangular Prism

Step-by-step explanation:

Given

The sketch in the attached diagram

Required

Determine the shape it represents

Analyzing the options 1 after the other

Triangular Prism:

This has 5 sides; 2 of which are triangles while the other are rectangles

Rectangular Prism

This, in other words represents a cuboid

Triangular Pyramid

This has 4 sides, all of which are triangles

Rectangular Pyramid

This has 5 sides; 4 of which are triangles while the last is a square of rectangle.

From the analysis above, the best option that answers the question is The Triangular Prism because it perfectly describes Lucia's drawing

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Slove it 3x-5=x+3 :)))))))

lidiya [134]

Answer:

x=4

Slove it 3x-5=x+3

3x-5=x+3

3x-x-5=3

2x-5=3

2x=3+5

2x=8

x=4

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3 years ago

Read 2 more answers

Can someone help me with this

Alexxandr [17]

Answer:

Step-by-step explanation:

the perimeter (P) of a rectangle is calculated as

P = 2l + 2w ( l is the length and w the width ) , then

P = 2(3 $\sqrt{15}$ ) + 2( $\sqrt{15}$ ) ← distribute both parenthesis )

= 6 $\sqrt{15}$ + 2 $\sqrt{15}$

= 8 $\sqrt{15}$

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2 years ago

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Rasek [7]

Answer

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Step-by-step explanation:

lemme know if it's good :)

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3 years ago

Emmett participated in a race. During the race, he ran 5 miles north and then ran 12 miles west. What is the shortest distance t

Lelechka [254]

I'd suggest you sketch this situation. If you did, you'd likely see right away that the shortest distance back to the starting point would be the hypotenuse of the right triangle whose legs are of lengths 5 miles and 12 miles.

Apply the Pythagorean Theorem to solve this.

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3 years ago

Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)

NemiM [27]

Call the parabola $P$ , parameterized by $\mathbf r(y)=\langle y^2+1,y\rangle$ with $0\le y\le 1\rangle$ . Then the work done by $\mathbf f(x,y)$ along $P$ is

$\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy$
$=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy$
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3 years ago