It should be B because you have to have 2 angles to know for sure.
Lets think they have cards, Alex = x , Gil = y and Meg = z. Then,
x+y+z = 740
Alex had 20 fewer cards than Gil. So,
x+20 = y
Alex had 120 fewer cards than Meg. So,
x+120 = z
x+(x+20)+(x+120) = 740
3x + 140 = 740
x= 200
y= 220
z= 320
<span>So Alex had 200 cards, Gil had 220 cards and Meg had 340 cards</span>
That’s how you plug it in and get the answer because when you plug in z and y value correctly you just have to follow the rule and simplify
So final answer would be +2
Answer:
1) 10.55%
2) 30.77%
Step-by-step explanation:
52/52•39/51•26/50•13/49 = 0.105498... ≈ 10.55%
100% chance you draw a unique card on the first draw
51 cards left of which 13(3) = 39 are unique suit for your second draw
50 cards left of which 13(2) = 26 are unique suit for your third draw
49 cards left of which 13(1) = 13 are unique suit for your forth draw.
Two balls are already green
Leaves 4 red balls in a field of 13 balls
4/13 = 0.307692... ≈ 30.77%
Answer:
Step-by-step explanation:
The picture of the question in the attached figure
we know that
----> by SOH (opposite side divided by the hypotenuse)
we have
solve for BC
substitute the values
