I can figure out this is a frefall motion.
Starting from rest => Vo = 0
Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)
d = width of a black/clear stripe pair = 5cm = 0.05m
g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)
t =√(2*0.05m/10m/s^2) = 0.1 s
Answer: approximately 0.1 s
Answer:
Step-by-step explanation:divide 12/10 and 24/10. The larger answer will tell you the slower ant... I’m pretty sure
U r going to subtract 3 from each side of the equation....leaving you with :
x^2 + 2x = -3
Answer:
Variable (or coefficients)
Step-by-step explanation:
