3 years ago

Can you find a whole number square root for all whole integers? Why or why not?

Mathematics

1 answer:

Neko [114]3 years ago

5 0

Answer:

im pretty shure you cant.

Step-by-step explanation:

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Answer:

$V = \frac{99}{7} x^{9}y^{-6}$

Step-by-step explanation:

Given

$V = \frac{4}{3}\pi r^3$

Required

Find V when

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Substitute $\frac{3}{2}x^3y^{-2$ for r in $V = \frac{4}{3}\pi r^3$

$V = \frac{4}{3}\pi * (\frac{3}{2}x^3y^{-2})^3$

Open bracket

$V = \frac{4}{3}\pi * \frac{3}{2}^3 * x^{3*3}y^{-2*3}$

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Simplify the fractions

$V = \pi * \frac{9}{2} * x^{9}y^{-6}$

Let

$\pi = \frac{22}{7}$

So:

$V = \frac{22}{7} * \frac{9}{2} * x^{9}y^{-6}$

$V = \frac{11}{7} * \frac{9}{1} * x^{9}y^{-6}$

$V = \frac{99}{7} * x^{9}y^{-6}$

$V = \frac{99}{7} x^{9}y^{-6}$

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Step-by-step explanation:

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