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3 years ago

What is the root of the polynomial equation x(x-2)(x+3)=18? Use a graphing calculator and a system of equations.

Mathematics

2 answers:

andre [41]3 years ago

4 0

Answer:

Step-by-step explanation:

notka56 [123]3 years ago

3 0

Answer:

The root of the polynomial equation x(x-2)(x+3)=18 is x=3

Step-by-step explanation:

x(x-2)(x+3)=18

Dividing both sides of the equation by x:

x(x-2)(x+3)/x=18/x

(x-2)(x+3)=18/x

We can use this system of equations:

(1) y=(x-2)(x+3)

(2) y=18/x

And using a graphing calculator we get:

x=3, y=6 → Point=(x,y)=(3,6)

Answer: The root of the polynomial equation x(x-2)(x+3)=18 is x=3

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Umnica [9.8K]

Answer: D, -13<-10

Step-by-step explanation:

Which ever way the open part of the '<' is facing, means that it is greater than the other number.

-13 is smaller than -10 so the open part of the symbol would face towards -10 and the pointy part would fact towards the -13.

Hope this helps :)

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