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Nikitich [7]
3 years ago
15

Find the volume of a rubber shell on a ball if the outer diameter of the ball is 24in and the inner diameter is 23.5in.

Mathematics
2 answers:
lakkis [162]3 years ago
6 0

Answer: 433.1

Step-by-step explanation: I haven’t figured the work out yet

Klio2033 [76]3 years ago
4 0

Answer:

433.1

Step-by-step explanation:

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A rectangle is placed around a semicircle as shown below. The length of the rectangle is 8 cm. Find the area of the shaded regio
icang [17]

Answer:

Area of the shaded region = 6.88 cm²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle - Area of the semicircle

Area of the rectangle = Length × Width

Length of the rectangle = AD = 8 cm

Width of the rectangle = OP = 4 cm [OP, OB and OC are the radii of the circle which are equal in measures]

Area of the rectangle = 8 × 4 = 32 cm²

Area of the semicircle = \frac{1}{2}\pi r^{2}

                                     = \frac{1}{2}\pi (OP)^{2}

                                     = \frac{1}{2}\pi (4)^{2}

                                     = 25.12 cm²

Area of the shaded region = 32 - 25.12

                                              = 6.88 cm²

3 0
3 years ago
Bobby is making a cake. The recipe calls for 1( 3)/(4) cups of flour for every( 1)/(8) cups of sugar. How many cups of flour is
PilotLPTM [1.2K]

Answer:

5 cups

Step-by-step explanation:

To get 1 cup of sugar, u must add 1/8 by 8. now you have one cup of sugar. But to find out how much flour u need, u also need to multiply 1 3/4 by 8, which gives u 5 cups

5 0
3 years ago
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What is the value of x?
dedylja [7]
It's A because a^2 +b^2
4 0
3 years ago
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Question is in the Picture.<br><br> A<br><br> B<br><br> C<br><br> D
oee [108]
B because 2 and 1/3 is 7/3 as an improper fraction times 4 is 28/3 and as a mixed number it is 9 and 1/3
7 0
3 years ago
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How to prove this using trig identities?
Pavlova-9 [17]

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

 

                      = (sin2B + cos2B)/[(cosB)(sinB)]

 

                       = 1/[(cosB)(sinB)]

 

                        = (1/cosB)(1/sinB)

 

                        = (secB)(cscB)

7 0
3 years ago
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