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iVinArrow [24]
3 years ago
8

4/5 x 7 need help asap​

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

4/5=0.8×7=5.6

5.6 is the answer

You might be interested in
Richard and Teo have a combined age of 26 . Richard is5 years older than twice​ Teo's age. How old are Richard and​ Teo?
loris [4]

Answer:Teo's age = 7 years ,Richard's age = 19 years

Step-by-step explanation:

Step 1

Let Teo's age be represented as x

Such that Richard 's age = 5 + 2x

and their combined ages equaling 26 can be expressed as

x + 5+ 2x = 26

Step 2 --- SOLVING

x + 5+ 2x = 26

3x+ 5= 26

3x= 26-5

3x= 21

x = 21/3

x = 7

Teo's age = 7 years

Richard's age = 5+2x= 5 + 14= 19 years

8 0
3 years ago
PLEASE HELP ASAP
blondinia [14]
- The Temperatures are on the top column numbers.

- The Wind speeds are on the left lateral numbers.

Answer: D, 23°F.

6 0
3 years ago
Question Help
Murljashka [212]

Answer:

b and a

Step-by-step explanation:

6 0
3 years ago
Juan is making t-shirts to sell at a concert.
o-na [289]

Answer:

7 shirts

Step-by-step explanation:

The function for producing shirts is

f($) = 50 + 7.5(x), where x is the number of shirt

The function for selling shirts is

f($) = 15(x)

For there to be a profit, he must make more money selling the shirts than he spent on making the shirts

Therefore, 15(x) > 50 + 7.5(x)

15x > 50 + 7.5x

15x - 7.5x > 50

7.5x > 50

x > 6.67 shirts

To make a profit, Juan must sell at least 7 shirts

7 0
2 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
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