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makvit [3.9K]
3 years ago
15

Write an equation perpendicular to the line 6x+12y=24 and passing through (4,0)

Mathematics
1 answer:
noname [10]3 years ago
6 0
Y = 2x - 8 is perpendicular to 6x+12y=24 and passes through (4,0)
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4 0
3 years ago
Solve the system by substitution.<br> - 8x + y = -32<br> - 3x – 10 = y<br> (,)
agasfer [191]

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Step-by-step explanation:

\begin{bmatrix}-8x+y=-32\\ -3x-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:-8x+y=-32:\quad x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}x=-\frac{-32-y}{8}\\\begin{bmatrix}-3\left(-\frac{-32-y}{8}\right)-10=y\end{bmatrix}\\\\Simplify\\\begin{bmatrix}\frac{3\left(-32-y\right)}{8}-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:\frac{3\left(-32-y\right)}{8}-10=y:\quad y=-16\\\\\mathrm{For\:}x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}y=-16\\x=-\frac{-32-\left(-16\right)}{8}\\

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3 years ago
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