Answer:
The probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

The information provided here is:
<em>p</em> = 0.27
<em>n</em> = 423
As <em>n </em>= 423 > 30, the sampling distribution of sample proportion can be approximated by the Normal distribution.
The mean and standard deviation of the sampling distribution of sample proportion are:

Compute the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% as follows:


*Use a <em>z</em>-table.
Thus, the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.
Answer:
10
Step-by-step explanation:
Answer:
The correct option is;

Step-by-step explanation:
Here we have the formula for the confidence interval of the difference of two means where the population standard deviation is unknown based on the sample mean and sample standard deviation is given as follows;

Where:
= Mean of the first sample = 22 grams
= Mean of the second sample = 18 grams
s₁ = Sample standard deviation of the first sample = 3.2 grams
s₂ = Sample standard deviation of the second sample = 2.1 grams
n₁ = Sample size of the first sample = 100
n₂ = Sample size of the second sample = 100
= t value obtained from tables at 99% confidence level and 100 degrees of freedom = 2.626 = 2.63
Therefore, plugging in the values, we have;

Therefore, the correct option is
.