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marishachu [46]
3 years ago
12

Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22. (Past studies have revealed that onl

y 86% of the booked passengers actually arrive for the flight.)Find the probability that if Air-USA books 24 persons, not enough seats will be available.prob =Is this probability low enough so that overbooking problems will be unusual? (Define unusual as having probability 5% or less)A. yes, it is low enoughB. no, it is not low enough
What about defining unusual as 10% or less?A. no, it is not low enoughB. yes, it is low enough
Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

B. no, it is not low enough

A. no, it is not low enough

Step-by-step explanation:

Given that Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22.

Prob for  a random person booked arrive for flight = 0.86

No of persons who books and arrive for flight, X is binomial, since there are two outcomes and each person is independent of the other

The probability that if Air-USA books 24 persons, not enough seats will be available

= P(X=23)+P(x=24)

= 0.1315

B. no, it is not low enough

-------------------------------

The prob we got is >10% also

A. no, it is not low enough

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Answer:

1) G(t) = 75 + \frac{23}{4}t\\

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Step-by-step explanation:

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Help!!!!¡¡¡¡ i need help solving this it will increase my letter grade!!!!
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Answer:

The answer is below⬇️⬇️

Step-by-step explanation:

f(x) = 3x+4

g(x) = 2x

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g(hx) = 2(x²+x-2)

= 2x²+2x-4

f(g(hx))=3(2x²+2x-4)+4

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=12x²+12x-16

f(g(f(g(hx))))=3(12x²+12x-16)+4

=36x²+36x-48+4

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