Answer:
ans: coefficient of 3rd term is 60
3rd term is 60x
Step-by-step explanation:
(5x +2)³ = C(3,2) × (5x)^(3-2) × 2²
= 3 × 5 × 4 × x
= 60x
Answer:
The area of the shaded portion of the figure is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.
step 1
Find the area of square ABCD
The area of square is equal to

where
b is the length side of the square
we have

substitute

step 2
We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
The area of circle is equal to

The diameter of the circle is equal to the length side of the square
so
---> radius is half the diameter
substitute


Therefore, the area of 2 "not-shaded" regions is:

and the area of 4 "not-shaded" regions is:

step 3
Find the area of the shaded region
Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:
so
---> exact value
assume

substitute
Answer:
55/43
Step-by-step explanation:
(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43
Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.
Answer:
65°
Step-by-step explanation:
The sum of the interior angles of a quadrilateral is 360 degrees.
65+115+115=295
360-295=65
Answer: 65°