Help asap please info in pic

Follow the order of operations to simplify <br>1. 60 ÷ 10×3 <br>2. 12 + 3×7 <br>3. 4×3+2×8

Paladinen [302]

1. 18
2. 33
3. 28

explain: division first so 6x3
multiply first so 12+21
multiply both then add so 12+16

5 0

3 years ago

2. Suppose 27 blackberry plants started growing in a yard. Absent constraint, the blackberry plants will spread by 80% a month.

Marta_Voda [28]

Explanation

The question indicates we should use a logistic model to estimate the number of plants after 5 months.

This can be done using the formula below;

$\begin{gathered} P(t)=\frac{K}{1+Ae^{-kt}};A=\frac{K-P_{0_{}}}{P_0}_{} \\ \text{From the question} \\ P_0=\text{ Initial Plants=27} \\ K=\text{Carrying capacity =140} \end{gathered}$

Workings

Step 1: We would need to get the value of A using the carrying capacity and initial plants that started growing in the yard.

This gives;

$\begin{gathered} A=\frac{140-27}{27} \\ A=\frac{113}{27} \end{gathered}$

Step 2: Substitute the value of A into the formula.

$P(t)=\frac{140}{1+\frac{113}{27}e^{-kt}}$

Step 3: Find the value of the constant k

Kindly recall that we are told that the plants increase by 80% after each month. Therefore, after one month we would have;

$\begin{gathered} P(1)=27+(\frac{80}{100}\times27) \\ P(1)=\frac{243}{5} \end{gathered}$

We can then have that after t= 1month

$\begin{gathered} \frac{140}{1+\frac{113}{27}e^{-k\times1}}=\frac{243}{5} \\ Flip\text{ the equation} \\ \frac{1+\frac{113}{27}e^{-k}}{140}=\frac{5}{243} \\ 243(1+\frac{113}{27}e^{-k})=700 \\ 243+1017e^{-k}=700 \\ 1017e^{-k}=700-243 \\ 1017e^{-k}=457 \\ e^{-k}=\frac{457}{1017} \\ -k=\ln (\frac{457}{1017}) \end{gathered}$

Step 4: Substitute -k back into the initial formula.

$\begin{gathered} P(t)=\frac{140}{1+\frac{113}{27}e^{\ln (\frac{457}{1017})t}} \\ =\frac{140}{1+\frac{113}{27}(e^{\ln (\frac{457}{1017})})^t} \\ P(t)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^t} \\ \end{gathered}$

The above model is can be used to find the population at any time in the future.

Therefore after 5 months, we can estimate the model to be;

$\begin{gathered} P(5)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^5} \\ P(5)=\frac{140}{1.07668} \\ P(5)=130.029\approx130 \end{gathered}$

Answer: The estimated number of plants after 5 months is 130 plants.

8 0

1 year ago

Teddy shirt has 10 brown buttons and 2 orange buttons. How many times as many brown buttons does his shirt have as orange button

Gelneren [198K]

5 times more brown buttons than orange buttons

6 0

3 years ago

Read 2 more answers

20 POINTS FOR GEOMETRY QUESTION!!

SIZIF [17.4K]

The answer is 1/4

Explanation
===============================
The question focuses on "if the student is known to be a boy..." we would obviously know that we would focous on only the total of the boys.

We have the formula for the probability of an event of happening which we would call event A (a boy being left-handed). P(A)= number of favorable outcomes/ total number of possible outcomes. The left-handers would go in the favorable outcomes since we want the probability of a boy being left handed and we would place the total boys in the total number of possible outcomes since all of them are going to be the one to be randomly picked. 50 left-handed/ 200 total boys. We have our fraction that is 50/200 as the probability but we can simplify it! We simplify 50/200 to get 1/4!!! 1/4 is the probability of a boy being picked that is left-handed!

Hope this helps!

6 0

4 years ago

How do i graph the equation -x + 2y = 2

Black_prince [1.1K]

<h2>Greetings!</h2>

Step-by-step explanation:

Firstly, set the x value as 0:

-0 + 2y = 2

2y = 2

y = 1

So when x = 0, y = 1

Now set y to 0:

-x + 2(0) = 2

-x = 2

x = -2

So when y = 0, x = -2

Simply plot the two following points:

(0 , 1) and (-2 , 0)

And don't forget to join these two points up!

Attatched is an image of this graph.

<h2>Hope this helps!</h2>

4 0

4 years ago