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How do you solve m - p/2 m=5 and p=2

navik [9.2K]

5-2/2
Divide first due to division coming before addition in pemdas
5-1
4

7 0

3 years ago

Use the properties you learned to show why (a+b)+c is equivalent to b+(a+c)

Vlad [161]

Using the Associative Property of addition, if you move the parentheses anywhere between a, b, and c, the answer will always be the same. Also, the Commutative Property of addition states that if you move the terms around, the answer is also still the same. So, (a+b)+c is the same as b+(a+c).

8 0

3 years ago

In a large on-the-job training program, half of the participants are female and half are male. In a random sample of six partici

Radda [10]

Answer: 0.9844

Step-by-step explanation:

given data:

sample size n = 6

It’s assumed that half the population are male and the remaining half are females

F = 1/2

M = 1/2

the probability that the investigator would draw altleats one male

P ( x ≥ 1 ) =

= 1 - ( 0.5 ) ^ 6

= ( 0.5 )^6

= 0.9844

5 0

3 years ago

The human resource department at a certain company wants to conduct a survey regarding worker benefits. The department has an al

dezoksy [38]

Answer:

Step-by-step explanation:

Hello!

A systematic sample is a sampling type where, the population units are listed in a certain order, the first unit is randomly chosen from the first k number of units and then the subsequent units are selected in intervals of k. To calculate k, in case you know the population size, you have to divide the population size by the sample size (usually established based on previous information. Remember k is always a whole number.

a) k= pob/n= 4247/40= 106.175 ≅ 106

b) From the 106 individuals you have to randomly select the first unit. Then starting from it the next 39 individuals surveyed will be the +k

Using a random number calculator I've chosen the first individual to be surveyed as number 57 after that you have to add k= 106 to know wich are the next individuals to be sampled:

1) 57 11) 1117 21) 2177 31) 3237

2) 57 + 106= 163 12) 1223 22) 2283 32) 3343

3) 269 13) 1329 23) 2389 33) 3449

4) 375 14) 1435 24) 2495 34) 3555

5) 481 15) 1541 25) 2601 35) 3661

6) 587 16) 1647 26) 2707 36) 3767

7) 693 17) 1753 27) 2813 37) 3873

8) 799 18) 1859 28) 2919 38) 3979

9) 905 19) 1965 29) 3025 39) 4085

10) 1011 20) 2071 30) 3131 40) 4191

I hope it helps!

3 0

3 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 437437 green peas and 129129 yellow peas. Use

navik [9.2K]

Answer:

The null hypothesis: $\mathbf{H_o: p=0.27}$

The alternative hypothesis: $\mathbf{H_1: p \neq 0.27}$

Test statistics : z = −2.30

P-value: = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and conclude that under the same circumstances the proportion of offspring peas will be yellow is not equal to 0.27

Step-by-step explanation:

From the given information:

Let's state the null and the alternative hypothesis;

Since The claim is that 27% of the offspring peas will be yellow.

The null hypothesis state that the proportion of offspring peas will be yellow is equal to 0.27.

i.e

$\mathbf{H_o: p=0.27}$

The alternative hypothesis state that the proportion of offspring peas will be yellow is not equal to 0.27

$\mathbf{H_1: p \neq 0.27}$

<u>The test statistics:</u>

we are given 437 green peas and 129 yellow apples;

Hence;

$\hat p = \dfrac{x}{n}$

where ;

$\hat p$ = sample proportion

x = number of success

n = total number of the sample size

$\hat p = \dfrac{129}{437+129}$

$\hat p = \dfrac{129}{566}$

$\mathbf{\hat p = 0.2279}$

Now; the test statistics can be computed as :

$z = \dfrac { \hat p -p }{\sqrt {\dfrac{p(1-p)}{n} } }$

$z = \dfrac {0.2279 -0.27 }{\sqrt {\dfrac{0.27(1-0.27)}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {\dfrac{0.27(0.73)}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {\dfrac{0.1971}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {3.48233216*10^{-4} } }$

$z = \dfrac {-0.043 }{0.01866} }$

z = −2.30

C. P-value

P-value = P(Z < z)

P-value = P(Z< -2.30)

By using the P-value method and the normal distribution as an approximation to the binomial distribution.

from the table of standard normal distribution

move left until the first column is reached. Note the value as –2.0

move upward until the top row is reached. Note the value as 0.30

find the probability value as 0.010724 by the intersection of the row and column values gives the area to the left of

z = -2.30

P- value = 2P(z ≤ -2.30)

P-value = 2 × 0.01072

P - value = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and conclude that under the same circumstances the proportion of offspring peas will be yellow is not equal to 0.27

8 0

3 years ago