Answer:
Area of Circle 1=>64(pi) units^2
Area of Circle 2=>9(pi) units^2
Step-by-step explanation:
Circumference=2(pi)r
Circle 1: 2(pi)r=16(pi)
Divide by 2(pi) on both sides
r=8 units
Area=(pi)r^2
Area of circle 1=>(pi)*(8^2)
Area of Circle 1=>64(pi) units^2
Circle 2: 2(pi)r=6(pi)
Divide by 2(pi) on both sides
r=3 units
Area=(pi)r^2
Area of circle 2=>(pi)*(3^2)
Area of Circle 2=>9(pi) units^2
8r and 4r are like terms since they both have an r
also 3s and -3s are also like terms because of the s
They could be 28 + 29 + 30
Answer:
y = 6
x = 2
Step-by-step explanation:
rearrange the first equation in terms of x
x = (y - 2)/2
substiute x in the second equation
y = -5[(y-2)/2] +16
Now simpilify and solve for y
y = (-5y + 10)/2 +16
y = -5/2y + 5 + 16
y + 5/2y = 5 + 16
3.5y = 21
y = 6
Now substitue y in the first equation to solve for x
x = (6 - 2)/2
x = 2
