3 years ago

Here is the histogram of a data distribution. All class widths are 1

Mathematics

2 answers:

timurjin [86]3 years ago

6 0

Answer:

Step-by-step explanation:

If it’s the green block from 2-6 with 6 being the tallest then it’s 6 a p e x

aev [14]3 years ago

3 0

Answer:

5.5

Step-by-step explanation:

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A) 121 <br> B) 102<br> C) 141 <br> D) 115

patriot [66]

Answer:

121

Step-by-step explanation:

cause if its on the oppsite side its going to be the same number

8 0

2 years ago

For circle O, mCD=125° and m

Burka [1]

CA is a diameter of the circle, so $m\widehat{AC}=180^\circ$ , which means $m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ$ . Then $m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ$ .

This means $m\angle CBO=55^\circ-35^\circ=20^\circ$ . Also, if $m\angle AOB=55^\circ$ , then $m\angle BOC=180^\circ-55^\circ=125^\circ$ , which in turns tells us that $m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ$ .