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Ilya [14]
3 years ago
14

Pls help it due in a hour

Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer:

The coordinates of the Midpoint of AB will be: (1/2, 5)

Step-by-step explanation:

Given the points

  • A(-2, 6)
  • B(3, 4)

Finding the midpoint between (-2, 6) and (3, 4)

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x_1,\:y_1\right)=\left(-2,\:6\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)

M.P=\left(\frac{3-2}{2},\:\frac{4+6}{2}\right)

        =\left(\frac{1}{2},\:5\right)

Therefore, the coordinates of the Midpoint of AB will be: (1/2, 5)

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The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha
erastova [34]

Answer:

106.63%.

Step-by-step explanation:  

We have been given that at the end of 2005, this price was $513. At the end of 2015, it was $1060.

To find the percentage of the price per ounce of gold increase we will use % increase formula.

\text{Percent Increase}=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100

Let us substitute our given values in above formula.

\text{Percent Increase}=\frac{1060-513}{513}\times 100

\text{Percent Increase}=\frac{547}{513}\times 100

\text{Percent Increase}=1.0662768031189084\times 100

\text{Percent Increase}=106.62768031189084\approx 106.63

Therefore, the price of per ounce of gold increased by 106.63%.

5 0
3 years ago
A light-year is 5.9 x 10^12 miles. A mile is approximately 6.34 x 10^4 inches. About how many inches are in a light-year? Write
NeTakaya
The answer would be 3.7406 × 10^17. Because when multiplying the constant you would get 37.406 and then you add the exponent and add one more since only one decimal can be over the decimal.
3 0
3 years ago
Solve for x -4(2x-3)= -36
ki77a [65]

Answer:

x=6

Step-by-step explanation:

-4(2x-3)=-36

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4 0
3 years ago
Points E, F, and D are on circle C, and angle G measures 60°. The measure of arc EF equals the measure of arc FD.
galben [10]

Answer:

∠EFD ≅ ∠EGD ⇒ A

Arc ED ≅ arc FD ⇒ C

m arc FD = 120° ⇒ E

Step-by-step explanation:

Let us revise some facts

  1. Equal chords subtended equal arcs
  2. The measure of an inscribed angle is one-half the measure of the central angle which subtended by the same arc
  3. The measure of a central angle is equal to the measure of its subtended arc
  4. If one angle of an isosceles triangle measure 60° then the triangle is equilateral
  5. The sum of the measures of the interior angles of any quadrilateral is 360°

In the quadrilateral  CDGE

∵ m∠G = 60°

∵ m∠GDC = m∠GEC = 90°

- By using the 5th rule above

∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°

∴ 60 + 90 + m∠DCE + 90 = 360

∴ 240 + m∠DCE = 360

- Subtract 240 from both sides

∵ m∠DCE = 120°

In circle C

∵ ∠DCE is a central angle subtended by arc DE

∵ ∠DFE is an inscribed angle subtended by arc DE

- By using the 2nd rule above

∴ m∠DFE = \frac{1}{2} m∠∠DCE

∵ m∠DCE = 120°

∴ m∠DFE = \frac{1}{2} (120)

∴ m∠DFE = 60°

- That means ∠EFD ≅ ∠EGD because their measure is 60°

∴ ∠EFD ≅ ∠EGD

In Δ EFD

∵ EF = FD

∵ m∠DFE = 60°

- By using the 4th rule above

∴ Δ EFD is an equilateral triangle

∴ ED = FD = FE

In circle C

∵ Side ED subtended by arc ED

∵ Side FD subtended by FD

∵ Side ED ≅ side FD ⇒ proved

- By using the 1st rule above

∴ Arc ED ≅ arc FD

∵ m∠ECD = 120°

∵ ∠ECD is a central angle subtended by arc ED

- By using the 3rd rule above

∴ m∠ECD = m arc ED

∴ m of arc ED = 120°

∵ Arc ED ≅ arc FD

∴ m arc ED = m arc FD

∴ m arc FD = 120°

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Answer C

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