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allochka39001 [22]
3 years ago
10

What the difference between wavelength and frequency

Mathematics
2 answers:
Viktor [21]3 years ago
7 0

Answer:     Wavelength is the distance between sound waves while frequency is the number of times in which the sound wave occurs.

Step-by-step explanation:

Ann [662]3 years ago
7 0

Answer:frequency is how fast something is coming (how frequent it is) and wave length is how long the light wave is traveling

Step-by-step explanation:

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A=75(125+81/2) how do you this equation? pls Help!!!
Maru [420]
Closing parenthesis is misplaced. Should be: 
<span>A = h(b₁ + b₂)/2 </span>

<span>h = 75 ft </span>
<span>b₁ = 125 ft </span>
<span>b₂ = 81 ft </span>

<span>Then it's just plug & grind: </span>

<span>A = 75(125 + 81)/2 ft² = 75·206/2 ft² = 75·103 ft² = (7500 + 225) ft² = 7725 ft² </span>

<span>If you follow that, it will guide you through any other, similar p</span>
4 0
2 years ago
Read 2 more answers
carbon-14 has a half-life of 5730 years. The formula f(t)=(1/2)^t/5730 give the percentage of carbon-14 left in the item after t
andreyandreev [35.5K]
Heyy sorry I need the points
5 0
2 years ago
-5/4x - 2)=-2(3 +6x)
Alex

Answer:

x = (-16)/43

Step-by-step explanation:

Solve for x:

(-5 x)/4 - 2 = -2 (6 x + 3)

Put each term in (-5 x)/4 - 2 over the common denominator 4: (-5 x)/4 - 2 = (-5 x)/4 - 8/4:

(-5 x)/4 - 8/4 = -2 (6 x + 3)

(-5 x)/4 - 8/4 = (-5 x - 8)/4:

(-5 x - 8)/4 = -2 (6 x + 3)

Multiply both sides by 4:

(4 (-5 x - 8))/4 = -2×4 (6 x + 3)

(4 (-5 x - 8))/4 = 4/4×(-5 x - 8) = -5 x - 8:

-5 x - 8 = -2×4 (6 x + 3)

4 (-2) = -8:

-5 x - 8 = -8 (6 x + 3)

Expand out terms of the right hand side:

-5 x - 8 = -48 x - 24

Add 48 x to both sides:

48 x - 5 x - 8 = (48 x - 48 x) - 24

48 x - 48 x = 0:

48 x - 5 x - 8 = -24

48 x - 5 x = 43 x:

43 x - 8 = -24

Add 8 to both sides:

43 x + (8 - 8) = 8 - 24

8 - 8 = 0:

43 x = 8 - 24

8 - 24 = -16:

43 x = -16

Divide both sides of 43 x = -16 by 43:

(43 x)/43 = (-16)/43

43/43 = 1:

Answer:  x = (-16)/43

8 0
3 years ago
Someone help with this <br> !!!
murzikaleks [220]

The correct answer is the third choice : 25/9

4 0
3 years ago
The number of phone calls between two​ cities, N, during a given time period varies directly as the populations p 1 and p 2 of t
kherson [118]

Answer:

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

Step-by-step explanation:

Given that,

The number of phone calls between two cities (N )

  • directly proportional as the value of populations p_1  and p_2  of two cities.
  • Inversely varies as the magnitude of distance (d).

N\propto\frac{p_1p_2}{d}

N=k.\frac{p_1p_2}{d}

Given that,

N=18,000, d=310 miles,  p_1=15,500 and p_2=180,000

18,000=k.\frac{15,500\times 180,000}{310}

\Rightarrow k=\frac{18,000\times310}{15,500\times 180,000}

\Rightarrow k=\frac{31}{15,500}

Now,

N=? , d=435 miles,  p_1=100,500 and p_2=160,000

N=\frac{31}{15,500}.\frac{100,000\times 160,000}{435}

\Rightarrow N\approx 73,563

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

5 0
3 years ago
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