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olga55 [171]
3 years ago
13

What are the factors of the following quadratic equation 12=x^2-x

Mathematics
1 answer:
Valentin [98]3 years ago
8 0
12 = x² - x
12 - 12 = x² - x - 12
0 = x² - x - 12
x² - x - 12 = 0
x = <u>-(-1) +/- √((-1)² - 4(1)(-12))</u>
                         2(1)
x = <u>1 +/- √(1 + 48)</u>
                 2
x = <u>1 +/- √(49)
</u>              2
x = <u>1 +/- 7</u>
           2
x = 0.5 +/- 3.5
x = 0.5 + 3.5        x = 0.5 - 3.5
x = 4                    x = -3
<u />
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