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nordsb [41]
3 years ago
5

Help me with this please​

Mathematics
1 answer:
Eduardwww [97]3 years ago
6 0

Answer:

A baseball diamond is a square with sides of 90 feet. What is the distance to the nearest tenth of a foot between home and second base?

Step-by-step explanation:

127.3 feet This problem requires the use of pythagoras theorem. Ignore the face that it's a baseball diamond. All you're concerned with is that you have a square that's 90 feet per side and you want to know what the length of the diagonal. So you have a right triangle with 2 sides of 90 feet each and you want to know the length of the hypotenuse. The formula is C^2 = A^2 + B^2 Both A and B are 90, so plugging them into the formula gives C^2 = 90^2 + 90^2 = 8100 + 8100 = 16200 So C^2 = 16200 Take the square root of both sides C = 127.2792 Round to the nearest tenth, giving C = 127.3

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D=m/v solve for v. Please help kinda urgent
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Answer:

v = m/D

Step-by-step explanation:

Step 1: Write equation

D = m/v

Step 2: Multiply both sides by v

Dv = m

Step 3: Divide both sides by D

v = m/D

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A student wondered if more than​ 10% of students enrolled in an introductory Chemistry class dropped before the midterm. He noti
Ilia_Sergeevich [38]

Answer:

C.It is a​ one-tailed test since the alternative hypothesis states that the parameter is greater than the hypothesized value.

Step-by-step explanation:

Let p be the percentage of students enrolled in an introductory Chemistry class dropped before the midterm. Then null and alternative hypotheses are:

H_{0}: p=10%

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3 Newton’s is how many pounds on earth
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8. Find the cube root of 27a^3+54a^2b+36ab^2+8b^3​
Tems11 [23]

Answer:

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is cube root of 27a^3+54a^2b+36ab^2+8b^3

3 0
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Read 2 more answers
4(3x^2y^4)^3 / (2x^3y^5)^4
tatyana61 [14]

Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

8 0
3 years ago
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