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3 years ago

Use the cross product property to solve each equation: 5/7 = x/9

Mathematics

1 answer:

enot [183]3 years ago

8 0

Answer:

x = 45/7

Step-by-step explanation:

$\frac{5}{7} =\frac{x}{9}$

Here, you can more easily see what the fractions look like.

In order to cross-multiply, you have to multiply 5 with 9, and 7 with x.

45 = 7x

Then, you isolate x by dividing 7 on both sides:

45/7 = x

Hope I helped :)

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Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

Two angles of a triangle measure 15° and 85°. What is the measure for the third angle

disa [49]

Answer:

15+85+x =180

X=180-15-85

X=8O°

Step-by-step explanation:

6 0

3 years ago

Name of devices is used for drawing curves which can't be drawn by a compass

Snowcat [4.5K]

A protractor can be used!

6 0

3 years ago

Determine whether the graphs shows growth or decay

mart [117]

Answer:

7) Decay

8) Growth

9) Growth

10) Growth

Step-by-step explanation:

7) As x increases, y is decreasing because as you add more value to the exponent, 1/3 gets smaller and smaller.

8) As x increases, y is increasing because as you add more value to the exponent, 2 gets bigger and bigger.

9) As x increases, y is increasing because as you add more value to the exponent, 2 gets bigger and bigger.

10) As x increases, y is increasing because as you add more value to the exponent, 2 gets bigger and bigger.

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2 years ago

80 units needed 6 units per case

hichkok12 [17]

Answer:

First time sending a shipment to Amazon Warehouse here.

I have a question in regards to filling information for my inventory.

I have a total of 20 BOXES ready to be sent. Each individual -BOX- contains 8 smaLL boxes inside. Each smaLL box contains 6 units.

Also, I should specify I’m sending 4 colors, same item. 4 -BOX- red, 4 -BOX- blue, 6 -BOX- steel, 6 -BOX- black. ( 20 BOXES total)

Would you fill it this way:

Review Shipment Contents:

Units Per Case — Number of Cases — Shipped

RED 48 — 4 — 192

BLUE 48 — 4 — 192

STEEL 48 — 6 — 288

BLACK 48 — 6 — 288

---TOTAL UNITS = 960

Shipping Service

SHIPMENT PACKING

ONE SKU PER BOX

SELECT PACK LIST FORMAT

File format Total # of boxes

20 ???

I’m counting Units Per Case as the total number of units in a BOX. And Number of Cases as the number of BOXES. Is this Right?

My confusion is differentiating BOXES and CASES.

I was also thinking about counting Each smaLL box as a Case (Units per Case =6 units) and Number of Cases would be “32”; 4 BOXES of one color , 32 CASES total.

I might be over complicating myself but really need your help on this one so I send the right information to Amazon.

5 0

3 years ago

Read 2 more answers