The polynomial cannot be factored in because it exists prime. Since 112 exists not a perfect square number so we cannot estimate the factors of the given equation.
<h3>What is a quadratic equation?</h3>
In a quadratic equation ax² + bx + c = 0
when (b² - 4ac) exists a perfect square only then we can factorize the equation.
In the given equation x² - 8x - 12 we have to determine the value of
b² - 4ac
From the equation, we get b = -8 and c = -12
b²- 4ac = (-8)² - 4(1)(-12)
= 64 + 48 = 112
Since 112 exists not a perfect square number so we can not estimate the factors of the given equation.
To learn more about quadratic equation refer to:
brainly.com/question/1214333
#SPJ4
Answer:
y = 3x + 19
Step-by-step explanation:
Point slope formula: y-y1=m(x-x1)
y - 4 = 3(x - (-5))
y - 4 = 3(x + 5)
y - 4 = 3x + 15
y = 3x + 19
Answer:
15w - 3
General Formulas and Concepts:
Step-by-step explanation:
<u>Step 1: Define expression</u>
13w + 22 + 2w - 25
<u>Step 2: Simplify</u>
- Combine like terms (w): 15w + 22 - 25
- Combine like terms (constants): 15w - 3
Ok, so we know that the radius of Sphere A is 24 cm, and we know that the diameter of Sphere B is 42 cm. To find the radius of Sphere B, all we need to do is divide the diameter by two. The radius of Sphere B is 21 cm. 24 times what factor is 21? Well,

is equal to 21. All we need to do now is simplify it. Divide the numerator and denominator by 3, and we get
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.
Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.

the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.