Answer:
G
Step-by-step explanation:
it gives an output for all real values.
Domain:all real values.
when x=-15
f(x)=0-32=-32
for all other values f(x)-32
so Range≥-32
4•7=28
4•-x=-4x
28-4x
In standard form, you always put the number with the variable first in the equation.
Answer: -4x+28
You add them up to see that it is in fact greater...
12.6+3.1+5.4=
21.1
Recall that the derivative of a function f(x) at a point x = c is given by
By substituting h = x - c, we have the equivalent expression
since if x approaches c, then h = x - c approaches c - c = 0.
The two given limits strongly resemble what we have here, so it's just a matter of identifying the f(x) and c.
For the first limit,
recall that sin(π/3) = √3/2. Then c = π/3 and f(x) = sin(x), and the limit is equal to the derivative of sin(x) at x = π/3. We have
and cos(π/3) = 1/2.
For the second limit,
we observe that e²ˣ = 1 if x = 0. So this limit is the derivative of e²ˣ at x = 0. We have
and 2e⁰ = 2.
Answer:
-5(p+3/5)=-4 what is the answer
The answer is P = 1/5
Step-by-step explanation:
from the question -5(p+3/5)=-4 applying the law of BODMAS we will use -5 to open the bracket
we have [-5(p) + -5×3/5] = -4
-5p - 3 =-4
collecting the like terms
we have; -5p = -4 + 3
-5p = -1
divide both sides by -5
we have; -5p/-5 = -1/-5
the minus sign cancels out and we have
p= 1/5
check your answer by sloting the value of p into the question -5(p+3/5)=-4
-5(1/5 + 3/5) = -4
-4=-4
