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3 years ago

∠DGC and ∠CGB are □ angles.Adjacent Adjacent Complementary Supplementary Vertical

Mathematics

2 answers:

dmitriy555 [2]3 years ago

6 0

Answer:

They are adjacent angles

Andrews [41]3 years ago

5 0

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Point O is the center of the circle. What is the value of X? <br> Answer options: 64, 54, 34, 44.

makkiz [27]

Answer:

34°

Step-by-step explanation:

The angle made when a tangent and a radius intersect=90°

Therefore angle OQP =90°

The triangle made by the two radii is isosceles ( base angles are equal) hence angle POQ=180-2(62)

=56°

The right triangle OPQ can hence be solved as follows

angle POQ=56°

angle OQP=90°

angle x=180-(56+90)=34° as all the interior angles of any triangle add up to 180°

4 0

3 years ago

Eric eats 1/6 of an apple pie and Jack eats 1/4 of the apple pie. How much of the pie has been eaten?

Genrish500 [490]

The answer is C) $\frac{7}{12}$

8 0

3 years ago

Read 2 more answers

What is the period and midline?

OverLord2011 [107]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\


\end{array}$

$\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}
$

so if you notice yours $\bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0

3 years ago

There are 6 blades on each windmill how many total blades are on 7 vwindmills? use fives facts to solves

aliina [53]

6 times 7 = 42 hope helped

8 0

3 years ago

the larger of two numbers is 1 more than 3 times the smaller. the diffrence is between 8 time the smaller and 2 tmies the larger

neonofarm [45]

Let the two numbers be x and y, with y being larger than x.
Then y=3x+1.
Also, 8x-2y= 10.

The first equation has already been solved for y. Substitute 3x+1 for y in the second equation:

8x-2(3x+1)=10, or 8x - 6x - 2 = 10, or 2x = 12 and x = 6.

If x = 6, then by the first equation y must be 3(6)+1, or 19.

The numbers are 6 and 19.

8 0

3 years ago