Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
Answer:
10.02%
Explanation:
The computation of the WACC is shown below. The formula of WACC is shown below:
= (Weightage of debt × cost of debt) + (Weightage of preferred stock) × (cost of preferred stock) + (Weightage of common stock) × (cost of common stock)
= 27% × 7.6% × (1 - 0.40) + 9% × 5.9% + 64% × 12.9%
= 2.052% × (1 - 0.40) + 0.531% + 8.256%
= 10.02%
Answer:
The Hi-Stakes Company
a. If the direct exchange rate increases, the dollar strengthens relative to the other currency.
b. If the indirect exchange rate increases, the dollar also strengthens relative to the other currency.
Explanation:
When the exchange rate increases, it means that more of the other currency is required in order to embark on importing and exporting transactions. However, the increases will weaken the ability of the importing currency to afford the dollar-based goods, which have then being made more expensive.
Answer:
DM Cost per Equivalent unit: 4.25
Explanation:
22400 beginning 60% materials 20% conversion
140,000 started
33600 ending 90% materials 40% conversion
Beginning Inventory
DM 71,160
DL 26,610
MO 20,110
Conversion Cost 46,720
Cost during the month
DM 618,800
DL 241,330
MO 513,600
Conversion Cost 754,930
Equivalent units Materials
22,400 * .4 8,960
140,000 140,000
33,600 * .1 (3,360)
145,600
DM Cost per Equivalent unit: 4.25
