Ask question

Ask question

All categories

2 years ago

13

aticengleSidesourcesActivitiesClassify the following triangle. Check all that apply.11.9132eA. equilateralB. obtusen C. rightD.

acuteE. isoscelesn F. scalene

1 answer:

Anuta_ua [19.1K]2 years ago

7 0

The triangle is obtuse and scalene.

You might be interested in

Shirley has earned $148 doing chores, but she wants to have earned at least $200 by the end of the week. if she does chores ever

asambeis [7]

Next 7 days
amount needed-amount now=amount in each day200-148=52
52 in 7 daysdivide by 752/7=7.4285round7.43
need to earn about $7.43 each day

5 0

2 years ago

The area of a rectangle is represented by the polynomial x^2+3x-6x-18. What are the length, width, and area of the rectangle if

Nitella [24]

Answer:

Length = 15

Width = 6

Area = 90

Step-by-step explanation:

Area of the rectangle = ${x}^{2} + 3x - 6x - 18$

Lets factorise the polynomial

$= > x(x + 3) - 6(x + 3)$

$= > (x + 3)(x - 6)$

We know that Area = Length × Width

Let the length be (x + 3) & width be (x - 6)

Its given in the question that x = 12. So putting the value of x gives ,

Length = $x + 3 = 12 + 3 = 15$

Width = $x - 6 = 12 - 6 = 6$

Area = Length × Width = 15 × 6 = 90

5 0

2 years ago

Failinggggggggggg mathhhhhhhhhhhhhhhhhhhhhhhhh

azamat

2. (D)
3. (B) Hope it helps

3 0

2 years ago

Read 2 more answers

Can anybody help me on this please I will be giving 15 points..

oksano4ka [1.4K]

Answer:

BC= $\sqrt{95}$

Angle A (or BAC)=54.31466...

Angle C (or ACB)=35.68533...

Step-by-step explanation:

$\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}$

$BC=\sqrt{12^2-7^2}$

$\sqrt{12^2-7^2}=\sqrt{95}$

$\frac{\sqrt{95}}{\sin \left(\angle \:BAC\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:BAC=54.31466$

$\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:ACB=35.68533$

4 0

3 years ago

Read 2 more answers

To prove a polygon is a rectangle which of the properties listed must be included in the proof

Zigmanuir [339]

Answer:

if the diagonals of a parallelogram are congruent, then it's a rectangle (neither the reverse of the definition nor the converse of a property). If a parallelogram contains a right angle, then it's a rectangle (neither the reverse of the definition nor the converse of a property).

Step-by-step explanation:

7 0

2 years ago