Ask question

Ask question

All categories

2 years ago

13

aticengleSidesourcesActivitiesClassify the following triangle. Check all that apply.11.9132eA. equilateralB. obtusen C. rightD.

acuteE. isoscelesn F. scalene

1 answer:

Anuta_ua [19.1K]2 years ago

7 0

The triangle is obtuse and scalene.

You might be interested in

How do you solve for 4y+20=5x

Dima020 [189]

You cant because there are 2 different variables

hope this helps, have a great day

3 0

3 years ago

Read 2 more answers

Strawberries at the farmer’s market are packaged in baskets weighing between 3 and 4 pounds. Each basket costs $2.50. Faiz spent

sammy [17]

12 to 16 pounds Im not very good at math but I hope this helps

7 0

2 years ago

Plz help<br> 15 + (-8) =

Effectus [21]

Answer:

7

Step-by-step explanation:

15 + (-8)

7

The answer would be 7 because you are only taking 15 plus negative 8 which would technically be the same as taking 15 minus 8, which would be 7.

Hope this helps! Please mark as brainliest! Thanks! Let me know if you need anymore help! :D

6 0

3 years ago

The USDA conducted tests for salmonella in produce grown in California. In an independent sample of 252 cultures obtained from w

Marat540 [252]

Answer:

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 252$

The number that tested positive is $k_1 = 18$

The second sample size is $n_2 = 476$

The number that tested positive is $k_2 = 20$

The level of significance is $\alpha = 0.01$

Generally the first sample proportion is mathematically represented as

$\^ p _1 = \frac{k_1 }{ n_1 }$

=> $\^ p _1 = \frac{18 }{ 252 }$

=> $\^ p _1 = 0.071$

Generally the second sample proportion is mathematically represented as

$\^ p _2 = \frac{k_2 }{ n_2 }$

=> $\^ p _2 = \frac{20 }{ 476}$

=> $\^ p _2 = 0.042$

The null hypothesis is $H_o : p_1 - p_2 = 0$

The alternative hypothesis is $H_a : p_1 - p_2 \ne 0$

Generally the test statistics is mathematically represented

$z = \frac{ \^ p_1 - \^ p_2 - ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1 } + \frac{\^ p_2 (1-\^ p_2)}{ n_2 } } }$

=> $z = \frac{ 0.071 - 0.042 - 0 }{ \sqrt{\frac{0.071 (1-0.071)}{ 252 } + \frac{0.042 (1-\^ 0.042)}{ 476 } } }$

=> $z = 1.56$

From the z table the area under the normal curve to the right corresponding to 1.56 is

$P(Z > 1.56 ) =0.05938$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > 1.56 )$

=> $p-value = 2 * 0.05938$

=> $p-value = 0.1188$

From the value obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

5 0

2 years ago

A gift basket has 2 soaps and 5 lotions and costs $20. A second basket has 6 spas and 15 lotions and cost $60. Is it possible to

kifflom [539]

A second basket has 6 spas--- I think you mean 6 soaps , so i will work with that

Answer:it is not possible to determine the price of the soap with the information given.

Step-by-step explanation:

Let s0ap be represented as x

and lotion be represented as y

2 soaps and 5 lotions costing $20 gives us equation 1 as

2 x+ 5y= 20-------- equation 1

second basket with 6 soaps and 15 lotions and costing $60 gives us equation 2 as

6x + 15y= 60------equation 2

Step 2 -- Solving

2 x+ 5y= 20-------- equation 1

6x + 15y= 60--------equation 2

BY elimination method, we multiply equation 1 by (3)

2x + 5y= 20 x (3)

6x + 15y=60-------equation 3

Subtraction of equation 3 from equation 2 gives us

6x + 15y=60-------equation 3

-6x + 15y= 60--------equation 2

0x +0y=0 which is no solution

Therefore it is not possible to determine the price of the soap

3 0

2 years ago