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3 years ago

Complete the square please.

Mathematics

1 answer:

Aleks04 [339]3 years ago

3 0

Answer:

(x-3)^2 + (y+2)^2 = 9^2

Step-by-step explanation:

x^2 -6x+y^2+4y-68 = 0

Complete the square

x^2 -6x+y^2+4y-68+68 = 0+68

x^2 -6x+y^2+4y = 68

Find the term to add for x

-6 /2 = -3 -3^2 = 9

Find the term to add for y

4/2 =2 2^2 = 4

Add 9 and 4

x^2 -6x+9+y^2+4y+4 = 68+9+4

(x-3)^2 + (y+2)^2 = 81

(x-3)^2 + (y+2)^2 = 9^2

The standard form is

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

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Help I will be marking brainliest!!!

expeople1 [14]

Answer:

A. 51°

Step-by-step explanation:

By the theorem of intersecting secants.

$m\angle B=\frac{1}{2} (m\widehat{LW} - m\widehat{MU})$

$44.5\degree =\frac{1}{2} (140\degree - m\widehat{MU})$

$2\times 44.5\degree = 140\degree - m\widehat{MU}$

$89\degree = 140\degree - m\widehat{MU}$

$m\widehat{MU} = 140\degree -89\degree$

$m\widehat{MU} = 51\degree$

8 0

3 years ago

Someone help me asap!

Sergeeva-Olga [200]

Answer: 5/2

5/6 / 1/3 = 2.5

2.5 in fraction = 5/2

5 0

3 years ago

Read 2 more answers

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

A particular shoe store stocks two styles of walking shoes. Style A sells for $66.95 and Style B sells for $84.95. At the end of

Gnom [1K]

Answer:

Style A shoes sold : 152

Style B shoes sold : 88

Step-by-step explanation:

Let :

Style A shoes = x
Style B shoes = y

Forming equations :

x = 2y - 24
66.95x + 84.95y = 17,652

Substitute the value of x from 1 in 2.

66.95 (2y - 24) + 84.95y = 17,652
133.90y - 1606.80 + 84.95y = 17,652
218.85y = 19258.80
y = 88

Finding x :

x = 2(88) - 24
x = 176 - 24
x = 152

Solution :

Style A shoes sold : 152
Style B shoes sold : 88

8 0

2 years ago

Given that rectangle MNOP~ rectangle STUV~, what is the length of ___ TU

IrinaK [193]

A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. The value of x or the length of TU is 22.5.

<h3>What is a rectangle?</h3>

That parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but the reverse statement may or may not be true.

Since all the rectangles are similar, therefore, the corresponding sides of the rectangle will be in ratio. Therefore,

$\dfrac{\text{Length of STUV}}{\text{Length of MNOP}} = \dfrac{9}{6}$

Similarly, the breadth will be,

$\dfrac{\text{Width of STUV}}{\text{Width of MNOP}} = \dfrac{\text{Length of STUV}}{\text{Length of MNOP}}\\\\\\\dfrac{\text{Width of STUV}}{\text{Width of MNOP}} = \dfrac{9}{6}\\\\\\\dfrac{x}{15}=\dfrac96\\\\\\x = \dfrac{9 \times 15}{6} = 22.5$

Hence, the value of x or the length of TU is 22.5.

Learn more about Rectangle:

brainly.com/question/15019502

#SPJ1

5 0

2 years ago