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Anvisha [2.4K]
3 years ago
5

Complete the square please.

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

(x-3)^2 + (y+2)^2 = 9^2

Step-by-step explanation:

x^2 -6x+y^2+4y-68 = 0

Complete the square

x^2 -6x+y^2+4y-68+68 = 0+68

x^2 -6x+y^2+4y = 68

Find the term to add for x

-6 /2 = -3  -3^2 = 9

Find the term to add for y

4/2 =2  2^2 = 4

Add 9 and 4

x^2 -6x+9+y^2+4y+4 = 68+9+4

(x-3)^2 + (y+2)^2 = 81

(x-3)^2 + (y+2)^2 = 9^2

The standard form is

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

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3 years ago
What is the product of − 3/11 and − 2/15? please explain.
emmainna [20.7K]

ANSWER

The product is

\frac{2}{55}

EXPLANATION

To find the product of

-  \frac{3}{11}

and

\frac{ - 2}{15}

means we should multiply the two fractions.

We multiply to obtain,

-  \frac{3}{11}  \times  -  \frac{2}{15}

=  -  \frac{3}{11}  \times  -  \frac{2}{3 \times 5}

Cancel the common factors:

=  -  \frac{1}{11}  \times  -  \frac{2}{5}

Now, multiply the numerators separately and the denominators too separately.

=  \frac{ - 1 \times  - 2}{11 \times 5}

This simplifies to,

= \frac{2}{55}

4 0
2 years ago
Solve the following equation. Round to the nearest hundredth.
mrs_skeptik [129]
F hope that helped have anger he try’s
4 0
2 years ago
Toby exercises 14 hours a week. John exercises 20% more than Toby and Jenny exercises two more hours than John. Which expression
sleet_krkn [62]
John exercised 20% more than Toby. So the number of hours that John exercises per week is 14 + 0.2(14) = 14 + 2.8 = 16.8.

Jenny exercises two more hours than John. So the number of hours that Jenny exercises per week is 16.8 + 2 = 18.8.

So an expression representing the number of hours that Jenny exercises after w weeks is 18.8w.
8 0
3 years ago
Read 2 more answers
Sin A 4/5.<br><br> Find<br> COSA + tan A
Ivahew [28]

Answer:

Step-by-step explanation:

The opposite side (the one not connected to A) = 4

The hypotenuse is 5

The adjacent side needs to be found for the cosine and the tangent.

a^2 + b^2 = c^2

a = opposite side = 4

b = adjacent side = ?

c = hypotenuse = 5

4^2 + x^2 = 5^2

16 + x^2 = 25          

x^2 = 25 - 16

x^2 = 9

x = sqrt(9)

x = 3

cos(A) = adjacent / hypotenuse = 3/5

Tan(A) = opposite / adjacent = 4/3

cos(A) + tan(A) = 3/5 + 4/3

cos(A) + tan(A) = 9/15 + 20/15 = 29/15

4 0
3 years ago
Read 2 more answers
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