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Anvisha [2.4K]
3 years ago
5

Complete the square please.

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

(x-3)^2 + (y+2)^2 = 9^2

Step-by-step explanation:

x^2 -6x+y^2+4y-68 = 0

Complete the square

x^2 -6x+y^2+4y-68+68 = 0+68

x^2 -6x+y^2+4y = 68

Find the term to add for x

-6 /2 = -3  -3^2 = 9

Find the term to add for y

4/2 =2  2^2 = 4

Add 9 and 4

x^2 -6x+9+y^2+4y+4 = 68+9+4

(x-3)^2 + (y+2)^2 = 81

(x-3)^2 + (y+2)^2 = 9^2

The standard form is

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

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Read 2 more answers
Please solve each of the following by factoring!
Oxana [17]

Answer:

see explanation

Step-by-step explanation:

(a)

x² - 36 = 0 ← is a difference of squares and factors as

(x - 6)(x + 6) = 0

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x + 6 = 0 ⇒ x = - 6

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(b)

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consider the product of the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

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(c)

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consider the product of the factors of the constant term (- 3) which sum to give the coefficient of the x- term (- 2)

the factors are + 1 and - 3 , since

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use these factors to split the x- term

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equate each factor to zero and solve for x

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