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AlekseyPX
3 years ago
5

The degree of the polynomial function f(x) is 3.

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

3rd graph.

Step-by-step explanation:

Roots of the equation are where the graph crosses the x axis.  So the bottom left (3rd) graph is correct.

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The area of a rectangle is 63m^2 and the length of the rectangle is 11m more than twice the width. Find the length and width.
AleksandrR [38]

Answer:

width = 3.5 m

length = 18 m

Step-by-step explanation:

area = length x width

x is the width then length = 2x + 11

x(2x + 11) = 63

2x^2 + 11x - 63 = 0

The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a

with a = 2

       b = 11

       c = -63

substitute in the formula

x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)

x = [-11 +/- √(121 + 504)]/4

x = [-11 +/- √625]/4

x = (-11 +/- 25)/4

x1 = (-11 + 25)/4 = 14/4 = 3.5

x2 = (-11 - 25)/4 = -36/4 = -9

since width can't be a negative number, x is 3.5

length = 2x + 11 = 2(3.5) + 11 = 18

7 0
2 years ago
Match the equation with its graph . identify the slope and y-intercept y= -2/3x+1
harkovskaia [24]

Answer:

the slope is -2/3x and the y intercept is 1

Step-by-step explanation:

3 0
3 years ago
What is the height of an object thrown when time is 6 seconds? Also explain how u got your answer
nevsk [136]

Answer:

946.4\ m

Step-by-step explanation:

Let

h(t) ---> the height of an object in meters

t ----> the time in seconds

we have

h(t)=-2.6t^2+40t+800

For t=6 sec

substitute in the quadratic equation  the value of t and solve for h

h(6)=-2.6(6)^2+40(6)+800

h(6)=946.4\ m

4 0
3 years ago
Write the following equation in the general form Ax + By + C = 0. 2x + y = 6
lesya [120]

Answer:

0.2x + y -6

Step-by-step explanation:

A and b are already there but to get c you just have to move 6 to the other side by subtracting it from the right side and adding it to the end of the left side.

8 0
3 years ago
X - 2y + 2z = -22 <br> x + 3y - z = 03 <br> x + 2y + 3z = -15
scZoUnD [109]
What is your question?
7 0
3 years ago
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