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AlekseyPX
3 years ago
5

The degree of the polynomial function f(x) is 3.

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

3rd graph.

Step-by-step explanation:

Roots of the equation are where the graph crosses the x axis.  So the bottom left (3rd) graph is correct.

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Which is the best estimate for written in scientific notation?
Amiraneli [1.4K]

I'm assuming you mean which one is written properly? It would be either 3 x 10^4 or 6 x 10^4.

Hope it helps!

6 0
4 years ago
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I need help on #17 can someone please help me?
sashaice [31]

Answer:

t=2

Step-by-step explanation:

We are given the equation

h = -16t²+36t+1

Next, we are asked to find how long the ball was in the air (the time, in seconds) if Casey caught the ball 9 feet above the ground (9 feet is the height).

Therefore, as 9 is the height, we can plug that into our equation to get

9 = -16t²+36t+1

To make this a quadratic equation that is easy to factor, we can subtract 9 from both sides to get

-16t²+36t-8=0

To factor this, we need to find two values that add up to 36 and multiply to (-16)*(-8) = 128. With a little guess and check, I found the numbers 32 and 4 to work well. We can then make the equation

-16t²+32t+4t-8=0

-16t(t-2) + 4(t-2) = 0

(-16t+4)(t-2) = 0

Therefore, to solve for the equation being 0, or 9 = -16t²+36t+1, either (t-2) or (-16t+4) must equal 0

t-2 = 0

t=2

-16t+4 = 0

-16t = -4

t = 1/4

Therefore, t=1/4 and/or t=2. To figure out which one it is (or both!), we can take into account that the question states "on its way down". This means that the ball goes up and then down, and we want to find t when it is going down. Using the knowledge that a ball that is hit goes up and then down, as well as that -16t²+36t-8=0 is a quadratic equation with 2 solutions, we can say that the higher value of t (t=2) represents when the ball is going down

3 0
3 years ago
A college is creating a new rectangular parking lot. the length is 0.17 mile longer than the width and the area of the parking l
Svetradugi [14.3K]
Let's call the width of the parking lot w.
The length of the parking lot if .17 more than the width so the length is w + .17

The parking lot is rectangular so its area is found by multiplying the length and the width. That is, the area is equal to what we obtain when we multiply w by w+.17. The area is: A = w(w+.17)= w^{2} +.17w

We are also told that the area is equal to .039 square miles so we set the expression we obtained for the area equal to .039 as follows.

w^{2} +.17w=.039

Since w represents the width of the rectangular lot, we can solve this equation for w to find the width. This is a quadratic equation (the highest exponent of the variable w is 2). We solve these by setting them equal to zero and then using the quadratic formula.

Setting our equation equal to zero (subtract .039 from both sides) gives us:
w^{2} +.17w-.039=0

The quadratic formula is as follows. Since the equation is in terms of w we write it as "w = ..." instead of the usual "x = ..."

w= \frac{-bplusminus \sqrt{ b^{2} -4ac} }{2a}

The part I write as "plusminus" is typically written with a + sign over a - sign. For right now let's leave it at that. Later in the problem we will see what it means and what to do with it.

To use the formula we have to identify a, b and c.

a is the coefficient of the squared term. That is, the number in front of w^{2} which here is 1.

b is the coefficient of the linear term. That is, the number in front of w which here is .17

c is the constant (the number by itself0 which is -.039

So we have:
a=1
b=.17
c=-.039

We plug these into the quadratic formula to obtain:
w= \frac{-.17plusminus \sqrt{ .17^{2} -(4)(1)(-.039)} }{(2)(1)}
w= \frac{-.17plusminus \sqrt{ .0289+.156} }{2}
w= \frac{-.17plusminus \sqrt{ .189} }{2}
w= \frac{-.17plusminus.43} {2}

Here is where the "pluminus" comes in. We continue to simplify the expression on the right but we split it in two. In one case we use "plus" and in the other "minus". That is, we add in one and subtract in the other. This gives us:
w= \frac{-.17+.43}{2}= \frac{.26}{2}=.13
and
w= \frac{-.17-.43}{2}= \frac{-.6}{2}=-.3

w is the width of the rectangular lot so it is a distance and cannot be measured using negative numbers. The width of the rectangular must be positive so we disregard the negative answer.

The width of the rectangle is .13 miles

Recall that the length of the rectangle is .17 more than the width. That is, the length is w+.17 and as we know the width to be .13 miles the length is .13 + .17 = .3 miles

The answer therefore is:
width = .13 miles
length = .3


4 0
3 years ago
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What is the area of a room in feet scaled at 1:20 when the measurements are 4 inches wide and 5 inches in length
Otrada [13]

Answer:

666.67 ft^2

Step-by-step explanation:

We start with a 4x5 scale room

We then use the 1:20 scale to multiply the 4 and the 5 by 20

4*20=80

5*20=100

We now have the dimensions of the actual room, 80in.x100in.

Area=length*width

A=100*80

A=8000 in^2

We are not done yet, though. To get feet, you convert inches to feet. 1 foot=12 inches.

8000/12=666.667, or 666.67, or 667, depending what you would round to

5 0
4 years ago
Mary is 9 years younger than anne. tom is twice older than anne. the sum of their ages is 95. how old is mary, tom and anne
horrorfan [7]
Mary is 17, Anne is 26, Tom is 52
7 0
3 years ago
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