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salantis [7]
3 years ago
9

PLEASE HELP ASAP

Mathematics
2 answers:
Sliva [168]3 years ago
7 0

Answer:

reflection across y

Step-by-step explanation:

nordsb [41]3 years ago
5 0
The reflection reflection on y axis
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Which of the following term describes √36 ? *
Cerrena [4.2K]

Step-by-step explanation:

A. Rational Number

square root 36 = 6/1

It can be write in a ratio.

7 0
3 years ago
What is 100,572×135,689
shepuryov [24]

Answer:

13646514108

Step-by-step explanation:

Used calculator.

5 0
3 years ago
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For the equation given below, evaluate y′ at the point (−2,2)<br> xe^y−4y=2x−4−2e^2
jeka94
Implicit differentiation
chain rule is important here

I'll show the steps partially
e^y+xe^yy'-4y'=2
xe^yy'-4y'=2-e^y
y'(xe^y-4)=2-e^y
y'=\dfrac{2-e^y}{xe^y-4}
now evaluate for (-2,2)
x=-2 and y=2
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{e^2-2}{2e^2+4}
that's it, simplest form
3 0
4 years ago
Which of the following sets of lengths can Sean use to make a right triangle?
Aleks [24]

Answer:

{8 cm, 15 cm, 17 cm}

Step-by-step explanation:

we know that

The length sides of a right triangle must satisfy the Pythagoras Theorem

so

c^2=a^2+b^2

where

c is the greater side (the hypotenuse)

a and b are the legs (perpendicular sides)

<u><em>Verify each case</em></u>

case 1) we have

{5 cm, 15 cm, 18 cm}

substitute in the formula

18^2=5^2+15^2

324=250 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 2) we have

{6 cm, 12 cm, 16 cm}

substitute in the formula

16^2=8^2+12^2

256=208 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 3) we have

{5 cm, 13 cm, 15 cm}

substitute in the formula

15^2=5^2+13^2

225=194 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 4) we have

{8 cm, 15 cm, 17 cm}

substitute in the formula

17^2=8^2+15^2

289=289 ----> is true

therefore

Sean can make a right triangle with this set of lengths

6 0
3 years ago
A survey of 340 randomly chosen US adults found that 60% of the 150 men and 50% of the 190 women ran a five-kilometer race durin
Andrej [43]

Answer:

The p-value is less than the significance level, so we will reject the null hypothesis, and conclude that at 5% significance level, the proportion for women that ran 5 km is more than the proportion of male that ran the 5 km. Thus, women are more likely to run the 5 km race.

Step-by-step explanation:

We are given;

Number of males selected; n₁ = 150

Number of females selected; n₂ = 190

Proportion of the males; p₁ = 0.6

Proportion of females; p₂ = 0.5

Let's define the hypotheses;

Null hypothesis; H0: p₁ ≥ p₂

Alternative hypothesis; Ha: p₁ < p₂

Now, the z score formula for this is;

z = (p₁ - p₂)/√(p^(1 - p^))(1/n₁ + 1/n₂))

Where;

p^ = (p₁ + p₂)/2

p^ = (0.6 + 0.5)/2

p^ = 0.55

Thus;

z = (0.6 - 0.5)/√(0.55(1 - 0.55))((1/150) + (1/190))

z = 0.1/0.0543

z = 1.84

From online p-value from z-score calculator attached, using z = 1.84, significance level = 0.05, one tailed hypothesis, we have;

P-value = 0.033

The p-value is less than the significance level, so we will reject the null hypothesis, and conclude that at 5% significance level, the proportion for women that ran 5 km is more than the proportion of male that ran the 5 km. Thus, women are more likely to run the 5 km race.

Although if we check at 0.01 significance level, we will not have the same answer as the p-value will be greater.

3 0
3 years ago
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