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Oxana [17]
3 years ago
12

In a certain candy store, 3 pounds of candy and 2 pounds of mints cost $10.80, and 1 pound of candy and 3 pounds of mints cost $

5.35. What is the cost per pound of the mints?
A.mints are 65¢ per lb
B.mints are 75¢ per lb
C.mints are 85¢ per lb
Mathematics
2 answers:
lesya692 [45]3 years ago
7 0
3 * C + 2 * M = 10.8

1 * C + 3 * M = 5.35

C = 3.1 $

M = 0.75 $ p

so B
Tasya [4]3 years ago
3 0
3c + 2 m = 10.80
1c + 3m = 5.35

Rewrite the second equation as: c = 5.35 - 3m
Now plug this new equation into the first equation in place of the c.

3(5.35 - 3m) + 2m = 10.80
16.05 - 9m + 2m = 10.80
Combine like terms
16.05 - 7m = 10.80
Subtract 16.05 from both sides
-7m = 10.80-16.05
-7m = -5.25
Divide both sides by -7
m = 5.25
m - .75
Letter B 75 cents per pound
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klemol [59]

Answer:

1480cm³

Step-by-step explanation:

The Equation for the Volume of a Cylinder is V=Bh, where B is the area of the circle (A= πr²).

We are given all of the things we need, we just have to plug them into the equation.

First let's find B using the radius(r) which is given to be 6.4cm, so B=πr²

B=π(6.4cm)²

Plug that into a calculator to get 128.6796351cm²

Now we can plug that into the original equation, V=Bh.

V=(128.6796351cm²)h

h is also given to be 11.5cm, so lets plug that in.

V=(128.6796351cm²)(11.5cm)

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3 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

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sergiy2304 [10]

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Step-by-step explanation:

He goes up 2 ½ but falls back down ½ so you take the two and do 15/2 and get 7.5 which is 7 ½ days.

4 0
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valentinak56 [21]

Answer:

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Step-by-step explanation:

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5 0
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