I need to know what 11, 14, and 15 are I don't remember how to do it

Mathematics

1 answer:

almond37 [142]2 years ago

6 0

When you reflect a function in the x-axis, the first coordinate of a point stays the same, and the second coordinate changes sign (what was positive is now negative and vice versa). See the attached picture.

Question 11: f(x) = -5x + 2. The function changes to its opposite, so g(x) = -(-5x + 2) = 5x - 2.

When you reflect a function in the y-axis, the first coordinate of a point changes to its opposite, but the second coordinate stays the same. Replace x with -x .

Question 14: f(x) = |2x - 1| + 3. Replacing x with -x produces g(x) = |2(-x) - 1| + 3 which simplifies to g(x) = |-2x -1| + 3.

Question 15 works the same way as #14.

You might be interested in

I need help putting correct answers in the yellow boxes.

olasank [31]

Answer:

-5 ± √5² - 4 · 1 · 4

2 · 1

Step-by-step explanation:

ax²+bx+c=0 (quadratic equation)

x= -b ± √b² - 4ac

a= 1

b= 5

c= 4

-5 ± √5² - 4 · 1 · 4

2 · 1

7 0

2 years ago

There are 10 balls in an urn, numbered from 1 to 10. If 5 balls are selected at random and their numbers are added, what is the

Kisachek [45]

Let $B_i$ denote the value on the $i$ -th drawn ball. We want to find the expectation of $S=B_1+B_2+B_3+B_4+B_5$ , which by linearity of expectation is

$E[S]=E\left[\displaystyle\sum_{i=1}^5B_i\right]=\sum_{i=1}^5E[B_i]$

(which is true regardless of whether the $X_i$ are independent!)

At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.

$P(X_i=x)=\begin{cases}\frac1{10}&\text{for }x\in\{1,2,\ldots,10\}\\0&\text{otherwise}\end{cases}$