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3 years ago

7

The debate team has m members. Each member sold 5 coupon books as a fundraiser. Write an expression that shows the number of cou

pon books the club sold.

1 answer:

Igoryamba3 years ago

5 0

The equation should be:
m x 5 = 5m

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A man buys 3 chicken sandwiches at 2.75 each and 2 cokes at 1.19 and the tax is $0.64. he gives you 11.52. how much change shoul

Artist 52 [7]

3 chicken sandwiches at $2.75 each: 3*2.75= 8.25

2 cokes at 1.19: 2*1.19= 2.38

Tax: 0.64

8.25+2.38+0.64= 11.27

He gives you 11.52, to find how much you need to give him back, subtract how much he gives you by the amount that is charged (11.27)

11.52-11.27= $0.25

3 0

3 years ago

Find the midpoint of the segment with the following endpoints. (5,3) and (1,9)

OLEGan [10]

Answer:

(3, 6)

Step-by-step explanation:

If you create a mini graph, like I did, you would have seen that the middle point is at the co-ordinates (3,6). I have attached a image to this reply, with my "graph". (Sorry if its a little ugly, but that doesn't matter, the math does.)

8 0

3 years ago

If f(x) =1/9 x-2, what is f-1(x)?

Sav [38]

Answer:

f^-1(x) = 9(x+2)

Step-by-step explanation:

To find the inverse function, exchange x and y and then solve for y

y = 1/9 x -2

Exchange x and y

x = 1/9 y-2

Solve for y

Add 2 to each side

x+2 = 1/9 y-2+2

x+2 = 1/9y

Multiply each side by 9

9(x+2) = 9*1/9y

9(x+2) = y

The inverse function

f^-1(x) = 9(x+2)

7 0

3 years ago

Read 2 more answers

100 POINTS. ASAP. PLS HELP!

IgorC [24]

Answer:

12.81%

Step-by-step explanation:

2600-5500=20500

20500/16=1281.25

1281.25/100= 12.8125

rounded 12.81%

7 0

3 years ago

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Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir

kati45 [8]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}$

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1$

well, the distance from the center to A is 1, namely is "inside the circle".

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6$

notice, the distance to B is exactly 6, and you know what that means.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398$

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

3 0

3 years ago

Read 2 more answers