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DIA [1.3K]
3 years ago
12

Parallel lines meet to form an acute angle true or falsehood

Mathematics
2 answers:
maks197457 [2]3 years ago
8 0
I believe it’s true sorry if I’m incorrect though
Katena32 [7]3 years ago
8 0

Answer:

false, parallel lines will never meet.

Step-by-step explanation:

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Use the unit circle to evaluate these expressions:
sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4

For this case we know that sin (\pi/4) = \frac{\sqrt{2}}{2}

So then sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

19 \pi/6 - 2\pi = \frac{7\pi}{6}

For this case we know that cos (\pi/6) = \frac{\sqrt{3}}{2}

And we know that \frac{7\pi}{6} is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}

c) For this case that any factor of \pi the sin function is equal to 0.

So from definition of tan we have this:

tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4

For this case we know that sin (\pi/4) = \frac{\sqrt{2}}{2}

So then sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

19 \pi/6 - 2\pi = \frac{7\pi}{6}

For this case we know that cos (\pi/6) = \frac{\sqrt{3}}{2}

And we know that \frac{7\pi}{6} is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}

c. tan(450pi)

For this case that any factor of \pi the sin function is equal to 0.

So from definition of tan we have this:

tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0

4 0
3 years ago
The capacity of a small glass is 120 ml. how many small glasses can be completely filled from a 2l pitcher of water?
Harman [31]
Total volume of pitcher = 2 l
Capacity of a small = 120 ml

2000 ml / 120 ml
200 / 12
16.5

It needs 16 full of cups and half cup
4 0
3 years ago
Read 2 more answers
How many different 5 digit street addresses can have the digits 4 7 3 4 and 8
Assoli18 [71]
60 street houses can use those digits.
4 0
4 years ago
Will make the first brainliest to answer
Papessa [141]
Gimme a second. The answer is 
C. 168 units 2

8 0
3 years ago
Read 2 more answers
PLS help me with thisss:((((((​
lara31 [8.8K]

Answer:

C and B

Step-by-step explanation:

(6)

\frac{3x-7y}{8} × \frac{6}{3x-7y} ← cancel 3x - 7y on numerator and denominator

= \frac{1}{8} × \frac{6}{1} = \frac{6}{8} = \frac{3}{4} → C

(7)

\frac{6x}{x^2-9} ÷ \frac{8}{4x-12}

Factorise the denominators of both fractions

x² - 9 = x² - 3² = (x - 3)(x + 3) ← difference of squares

4x - 12 ← factor out 4 from each term

= 4(x - 3)

Then rewrite as

\frac{6x}{(x-3)(x+3)} ÷ \frac{8}{4(x-3)} ← cancel 8 and 4 by 4

= \frac{6x}{(x-3)(x+3)} ÷ \frac{2}{x-3}

• leave first fraction, change ÷ to × , turn second fraction ' upside down'

= \frac{6x}{(x-3)(x+3)} × \frac{x-3}{2} ← cancel x - 3 on numerator and denominator

= \frac{6x}{x+3} × \frac{1}{2} ← cancel 2 and 6 on numerator and denominator

= \frac{3x}{x+3} → B

8 0
3 years ago
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