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Hoochie [10]
3 years ago
11

What is a reasonable distance between two cities? A. 200 km B. 200 m C. 200 cm D. 200 mm

Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

200 KM  about 124 miles

Step-by-step explanation:

200 m is only 0.12 miles

200 cm is 78 inches

200 mm is 20 cm or 7.8 inches

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A magician charges parties a $30 fee to cover travel and miscellaneous expenses plus $19.99 per hour. What an equation for that?
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Answer:

30 + 19.99 per hour

Step-by-step explanation:

ADD THEM IN A EQUATION.

SO SIMPLE TO DO THAT!

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What is the slope that passes through the lines (2.1,-4.2) and (2.5,-5)
Usimov [2.4K]

slope = (y2-y1)/(x2-x1)

 = (-5--4.2) /(2.5 -2.1)

(-5+4.2)/(2.5-2.1)

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7 0
3 years ago
An integer is 5 more than 4 times another. If the product of the two integers is 51, then find the integers.
Yakvenalex [24]

Answer:

  • <u>3 </u><u>and</u><u> 17</u> are required integers

Step-by-step explanation:

  • Let one integer be x
  • And other integer be y

x = 4y + 5

xy = 51

<u>According to </u><u>question </u><u>:</u>

➞ (4y + 5)y = 51

➞ 4y² + 5y = 51

➞ 4y² + 5y - 51 = 0

➞ 4y² + 17y - 12y - 51 = 0

➞ y (4y + 17) - 3(4y + 17) = 0

➞ (y - 3)(4y - 17) = 0

➞ y - 3 = 0

➞ <u>y = 3</u>

Hence,

➞ <u>y = 3</u>

➞ x = 4y + 5

➞ x = 4 (3) + 5

➞ x = 12 + 5

➞<u> </u><u>x = 17</u>

∴ The required integers are <u>3 and 17</u>

7 0
2 years ago
A candy box is made from a piece of cardboard that measures 23 by 13 inches. Squares of equal size will be cut out of each corne
wolverine [178]

Answer:

2.67 inches.

Step-by-step explanation:

Assuming that we represent the size of the squares with the letter y, such that after the squares are being cut from each corner, the rectangular length of the box that is formed can now be ( 23 - 2y), the width to be (13 - 2y) and the height be (x).

The formula for a rectangular box = L × B × W

= (23 -2y)(13-2y) (y)

= (299 - 46y - 26y + 4y²)y

= 299y - 72y² + 4y³

Now for the maximum volume:

dV/dy = 0

This implies that:

299y - 72y² + 4y³ = 299 - 144y + 12y² = 0

By using the quadratic formula; we have :

= \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}

where;

a = 12; b = -144 and c = 299

= \dfrac{-(-144) \pm \sqrt{(-144)^2 -4(12)(299)}}{2(12)}

= \dfrac{144 \pm \sqrt{20736 -14352}}{24}

= \dfrac{144 \pm \sqrt{6384}}{24}

= \dfrac{144 \pm79.90}{24}

= \dfrac{144 + 79.90}{24} \ \  OR  \ \   \dfrac{144 - 79.90}{24}

= 9.33 \ \  OR  \ \ 2.67

Since the width is 13 inches., it can't be possible for the size of the square to be cut to be 9.33

Thus, the size of the square to be cut out from each corner to obtain the maximum volume is 2.67 inches.

3 0
3 years ago
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