2(3x-5) + 2(-2x+10)
6x-10 + -4x+ 20
=2x+ 10
Answer:
15
Step-by-step explanation:
Step-by-step explanation:
MID POINT =[(X1 +X2)/2 , (Y1 +Y2)/2]
WE KNKW THAT A(2,–8) AND THE MID POINT IS (3,3)
SUBSTITUTING INTO THE EQUATION ABOVE
(3,3) = [(2+ X2)/2 ,(–8+ Y2)/2]
EQUATING THE X COORDINATES
=> 3 = (2+ X2)/2 (CROSS MULTIPLY)
=> 6 = 2 + X2
X(subscript 2)= 4
EQUATING THE Y COORDINATES
=> 3 =(–8 +Y2)/2 (CROSS MULTIPLY)
6 = –8 +Y2
=> Y(subscript 2)= 14
THEREFORE THE COORDINATES OF B ARE (4 ,14)
hope this helps :)
The problem to number 1 is a inequality, so
x-2<-7
x<-5
since it is < it will have open dot.
Answer: C
2. x/3>-3
x>-9
Answer: D
3. 5p+26<72
5p<46
p<9.2
Answer: C
4. -3w+3>=18
-3w>=15
x<=-5
5. 15x-21>= 12x+18
x>=13
Answer A
6: |3x|=15
Absolute values positive so {-5,5}
Answer: B
7: |2x-3|=5
x=4,-1
Answer: C